Draw a diagram to illustrate the problem as shown below.
When the smaller gear rotates through a revolution, it sweeps an arc length of
2π(4) = 8π inches.
Part 1
The same arc length is swept by the larger gear. The central angle of the larger gear, x, is
7x = 8π
x = (8π)/7 radians = (8π)/7 * (180/π) = 205.7°
Answer: 205.7° (nearest tenth)
Part 2
When the larger gear makes one rotation, it sweeps an arc length of
2π(7) = 14π inches.
If the central angle for the smaller gear is y radians, then
4y = 14π
y = 3.5π radians = (3.5π)/2π revolutions = 1.75 revolutions
Answer:
The smaller gear makes 1.75 rotations
Answer:
40/9
Step-by-step explanation:
9y = -8x + 40
y = -8/9x + 40/9
The circumference is the diameter times PI
The exact circumference would be 9PI cm
The approximate circumference would be 9 x 3.14 = 28.26 cm
Answer:
Step-by-step explanation:
<u>Given</u>
- Q = 7m + 3n,
- R = 11 - 2m,
- S = n + 5,
- T = -m - 3n + 8
<u>Simplify [Q - R] + [S - T]</u>
- (7m + 3n - (11 - 2m)) + (n + 5 - (-m - 3n + 8)) =
- 7m + 3n -11 + 2m + n + 5 + m + 3n - 8 =
- m(7 + 2 + 1) + n(3 + 1 + 3) - 14 =
- 10m + 7n - 14