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valentina_108 [34]
3 years ago
6

Please help me solve this!!

Mathematics
1 answer:
Studentka2010 [4]3 years ago
3 0

Answer:

WR = 26

Step-by-step explanation:

Givens

UT = 10

VS = 18

WR = ??

Formula

(WR + UT) / 2 = VS

Solution

Substitute

(WR + 10) /2 = 18

Multiply both sides by 2

(WR + 10/2 * 2 = 18 * 2

Do the multiplication

WR + 10 = 36  

Subtract  10 from both sides

WR + 10 - 10 = 36 - 10

WR = 26

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The solutions to f(x) = 64 is x = 7 and x = –7.

Solution:

Given data:

$f(x)=x^{2}+15 – – – – (1)

f(x)=64 – – – – (2)

To find the solutions to f(x) = 64.

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Read 2 more answers
Please help radical expression dividing
77julia77 [94]
\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad &#10;\begin{cases}&#10;63=3\cdot 3\cdot 7\\&#10;6=2\cdot 3&#10;\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}&#10;\\\\\\&#10;\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}

\bf \textit{now, rationalizing the denominator}\\\\&#10;\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}&#10;\\\\\\&#10;\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.
6 0
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