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Harlamova29_29 [7]
3 years ago
5

Help please time limit...Amanda is choosing between two exercise routines.

Mathematics
1 answer:
Marina86 [1]3 years ago
7 0

Amanda must spend more than 8 minutes on Routine #1 to burn more calories than Routine #2.

Step-by-step explanation:

Routine # 1;

Calories burned in running = 15.5 per minute

Let,

t be the minutes spent running.

T = total calories burned

T = 15.5t

Routine # 2;

Calories burned while walking = 22 calories

Calories burned while running = 12.75 per minute

T = 12.75t + 22

For burning more calories in Routine 1;

Routine 1 > Routine 2

15.5t>12.75t+22\\15.5t-12.75t>22\\2.75t>22\\

Dividing both sides by 2.75

\frac{2.75t}{2.75}>\frac{22}{2.75}\\t>8

Amanda must spend more than 8 minutes on Routine #1 to burn more calories than Routine #2.

Keywords: linear inequality, division

Learn more about division at:

  • brainly.com/question/9136949
  • brainly.com/question/909890

#LearnwithBrainly

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There is a total of 2,512 people attending the fun fair. 5/8 of sttemdees are students and 1/4 of attendees are parents. the res
kvv77 [185]

Answer:

<u>314 of the people attending the fun fair are people living in the neighborhood</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Number of people attending the fun fair = 2,512

Fraction of people attending the fun fair that are students = 5/8

Fraction of people attending the fun fair that are parents = 1/4

Rest of the people attending the fun fair lives in the neighborhood

2. Let's calculate the number of students, parents and people living in the neighborhood

Students:

Fraction of people attending the fun fair that are students = 5/8

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1,570 of the people attending the fun fair are students

Parents:

Fraction of people attending the fun fair that are parents = 1/4

1/4 * 2,512 = 628

628 of the people attending the fun fair are parents

People living in the neighborhood

2,512 - 1,570 - 628 = 314

<u>314 of the people attending the fun fair are people living in the neighborhood</u>

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Step-by-step explanation:

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