Answer:
0.0416
Step-by-step explanation:
Given :
Sample size, n = 300
Sample mean, x = 35.5
Population mean, m = 35
Standard deviation, s = 5
The test statistic :
Zstatistic = (x - m) / s/sqrt(n)
Zstatistic = (35.5 - 35) / 5/sqrt(300)
Zstatistic = 0.5 / 0.2886751
Zstatistic = 1.732
Using the p value calculator from Zstatistic :
One tailed P value at 95% confidence interval is : 0.0416
20{5[100-2(50)+20]}
20{5[100-100+20]}
20{5[20]}
20(100)
20000
your answer would be the last answer choice