For this case, the area is given by:
A = x * (200-2x)
Rewriting:
A = 200x-2x ^ 2
Deriving the expression we have:
A '= 200-4x
Equaling zero we have:
200-4x = 0
We clear x:
4x = 200
x = 200/4
x = 50 feet
Then, the maximum area is:
A (50) = 50 * (200-2 * 50)
A (50) = 5000 feet ^ 2
Answer:
the maximum possible area that can be enclosed with his 200ft of fencing is:
A (50) = 5000 feet ^ 2
O.o that so hard but my big sister know how to do it
The percent markup would be 40%. 10+40%=14
Hope this helps!
Can u plz mark me as brainliest? I really need it!
If sounds travel 335 meters in 1 second , in 1 minute it travels 60 times that distance :
335m × 60 = 20100 meters
Sounds travel 20100 meters per minute
if 1000 meters = 1 km ,
20100 meters = 20100/1000 km
20100 meters = 20.1 Km
Awnser : Sound would travel 20.1 km in one minute
Answer:
255,024
Step-by-step explanation:
24 x 23 x 22 x 21
24 options for the first member
23 options for the second member
22 options for the third member
21 options for the last member
