Answer:
x = 3
Step-by-step explanation:
7/x - 3/(2x) + 7/6 = 9/x
x(7/x - 3/(2x) + 7/6) = x(9x)
x*7/x - 3*x/(2x) + x*7/6 = x*9x
7 - 3/2 + 7x/6 = 9
7x/6 = 9 - 7 + 3/2
7x/6 = 2 + 3/2
7x/6 = 12/6 + 9/6
7x = 12+9
7x = 21
x = 21/7
x = 3
probe:
7/3 - 3/(2*3) + 7/6 = 9/3
14/6 - 3/6 + 7/6 = 3
(14 - 3 + 7) / 6 = 3
18/6 = 3
Answer:
The ratio of the perimeter of ABCD to JKLM is;
b. 3/5
Step-by-step explanation:
Given that ABCD ~ JKLM, where;
DC and ML are corresponding sides
AD and JM are corresponding sides
AB and JK are corresponding sides
Therefore;
DC/ML = AD/JM = AB/JK
Plugging in the values of the variables gives;
9/15 = z/10 = x/12
∴ z = 10×9/15 = 6
x = 12×9/15 = 7.2
9/15 = 6/y
y = 6 ×15/9 = 10
The perimeter of the quadrilateral ABCD = AB + BC + DC + AD
∴ The perimeter of the quadrilateral ABCD = 6 + 6 + 9 + 7.2 = 28.2
The perimeter of the quadrilateral JKLM = JK + JM + ML + LK
∴ The perimeter of the quadrilateral JKLM = 12 + 10 + 15 + 10 = 47
The ratio of the perimeter of ABCD to JKLM = 28.2/47 =0.6 = 3/5.
When you have an equation with two variables, it's easier to graph it in the form y=mx+b. b is the y-intercept - the x-value at which y is equal to zero, and m is the slope of the graph.
So if I have the equation 3x+2y=12, I have to first subtract 3x from both sides.
2y=-3x+12. Now I have to divide the whole thing by 2 to get my y value alone. y=-3/2x+6.
Now, to graph it, I have to first plot the point where y equals zero and x equals six. Then you plug in different numbers above and below this. When x=5, you get y=-3/2*5 + 6 which is -1.5. So you have the point (5, -1.5) and also the point (6, 0). You can plug in 0 for y and solve for x to find the x-intercept, or when x=0. 0=-3/2x+6. Subtract six from both sides. -6=-3/2x. Divide both sides by -3/2. 4=x. So you have another point - (4,0).
Now that you have three points, you can connect them with a line and add arrows to the end.
Hope I helped!
