so, we have two 54x18 rectangles, so their perimeter is simply all those units added together, 54+54+54+54+18+18+18+18 = 288.
we know the circle's diameter is 1.5 times the width, well, the width is 18, so the diameter of the circle must be 1.5*18 = 27.
![\bf \stackrel{\textit{circumference of a circle}}{C=d\pi }~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=27 \end{cases}\implies C=27\pi \implies C=\stackrel{\pi =3.14}{84.78} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the rectangles}}{288}~~~~+~~~~\stackrel{\textit{perimeter of the circle}}{84.78}~~~~=~~~~372.78](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bcircumference%20of%20a%20circle%7D%7D%7BC%3Dd%5Cpi%20%7D~~%20%5Cbegin%7Bcases%7D%20d%3Ddiameter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20d%3D27%20%5Cend%7Bcases%7D%5Cimplies%20C%3D27%5Cpi%20%5Cimplies%20C%3D%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B84.78%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20rectangles%7D%7D%7B288%7D~~~~%2B~~~~%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20circle%7D%7D%7B84.78%7D~~~~%3D~~~~372.78)
Permutations are written as nPx where n is the number of total choices possible and x is the number of choices that will be used. This is calculated as nPx = n! / (n-x)!.
Permutations represent the number of ways we can choose x objects from n possibilities where the order of selection matters.
Answer:
12 cm
Step-by-step explanation:
multiply 10 by .2
10 × .2 = 2
add 2 to 10
2 + 10 = 12 cm
Answer: 27x²yz + 3xz² - 2xy - 2y²z + 2yz²
<u>Step-by-step explanation:</u>
Use the distributive property.
3xz(9xy + z) - 2yz(x + y - z)
= 3xz(9xy) + 3xz(z) -2yz(x) -2yz(y) -2yz(-z)
= 27x²yz + 3xz² -2xy -2y²z +2yz²
4r+2=-26
4r=-28 (subtract 2 from both sides)
r=-7 (divide both sides by 4)
