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3 years ago

Please help! How do I solve this?

Mathematics

1 answer:

Advocard [28]3 years ago

5 0

$m\angle 6=m\angle3\\
8x+7=6x+32\\
2x=25\\
x=12.5\\\\
m\angle 6=8\cdot12.5+7=100+7=107\Rightarrow D
$

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Caitlyn did 6/7 of the problems on her math correctly and 4 incorrectly. She did all the problems. How many were there?

Viefleur [7K]

If $\frac{6}{7}$ were incorrect, it means that $\frac{1}{7}=4$ were correct
$4*7=28$
There were 28 problems ;)

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2 years ago

Consider the following polynomial.

vfiekz [6]

Answer:

The equivalent factored form of this equation is (x² + 49)(x - 6)

Step-by-step explanation:

x³ - 6x² + 49x - 294

First, group the first and second terms together and group the last two terms together.

(x³ - 6x²) + (49x - 294)

Find the greatest common factor of both parentheses and factor them.

x²(x - 6) + 49(x - 6)

Now, since the two terms in the parentheses are the same, then we have factored the equation correctly.

So, the factored form of the equation is (x² + 49)(x - 6)

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2 years ago

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Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

eduard

If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

_______________

$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus

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2 years ago

The diameter of a Frisbee is 12 inches. what's the area of the Frisbee?

xenn [34]

A= πr² = π × 6² = "113.1" is the area of the frisbee.

Please put me as brainliest.

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3 years ago

Find the value of x that makes the quadrilateral a parallelogram. 3x + 5 5x - 9 X =

Lady bird [3.3K]

Answer:

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3x-5x= -9-5

-2x=-14

x= -14/-2

x=7

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2 years ago

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