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tatiyna
3 years ago
10

How do i solve for (2x/5)+1=13/5

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
5 0

Answer:

x = 4

Step-by-step explanation:

  1. \frac{2x}{5} +1 = \frac{13}{5}  
  2. \frac{2x+5}{5} = \frac{13}{5} divide both sides by 5
  3. 2x + 5 = 13 subtract 5 from both sides
  4. 2x = 8 divide both sides by 2
  5. x = 4
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stira [4]

Answer:

Option A -  The distance Train A traveled in 1 h is equal to the distance Train B traveled in 1 h.

Step-by-step explanation:

Given : The distance Train A traveled is modeled by the function d(t)=81t

where d represents distance in miles and t represents time in hours.

To find : How does the distance Train A traveled in 1 hour compare to the distance Train B traveled in 1 hour?

Solution :

Distance traveled by Train A in 1 hour is

d(t)=81t

d(t)=81(1)=81

Distance traveled by Train B in 1 hour is

d(t)=81t

d(t)=81(1)=81

or for B, we have 324 miles in 4 hours. If that is at a constant speed, it travels 324/4 = 81 miles in one hour

Therefore, The distance Train A traveled in 1 h is equal to the distance Train B traveled in 1 h.

Hence, Option A is correct.


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3 years ago
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nevsk [136]

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5 0
3 years ago
PLEASE HELP QUESTION IN PICTURE
sp2606 [1]

Answer:

b = 55

d = 55

Step-by-step explanation:

Part B:

1. We can see that m∠C (25 degrees), the angle with 100 degrees, and ∠B are adjacent angles that add up to 180 degrees.

  • This means that b + 25 + 100 = 180

2. (Solving equation above)

Step 1: Simplify both sides of the equation.

  • b + (25+100)=180
  • b + 125 = 180

Step 2: Subtract 125 from both sides.

  • b + 125 - 125 = 180 - 125
  • b = 55

Therefore, b = 55.

Part D:

1. The exterior angle theorem states that the exterior angle of a triangle is congruent to the sum of the two opposing interior angles.

  • This means that 110 = d + 55

2. (Solving)

Step 1: Subtract 55 from both sides.

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Therefore, d = 55.

5 0
2 years ago
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oee [108]

Las funciones trigonométricas se utilizan fundamentalmente en la solución de triángulos

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interiores suman 180°. La notación que se acostumbra es la siguiente.

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3 years ago
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