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algol [13]
3 years ago
9

Find two numbers whose sum is 23 and whose product is a maximum.

Mathematics
1 answer:
Galina-37 [17]3 years ago
7 0
Let x = the first numberLet y = the second number x + y = 23                    eq1       y = 23- x 
xy = Product                 eq2

Substitute eq1 into eq2.  Lets get eq2 in terms of x.  

Product = x(23 - x)Product = - x2 + 23x
 
we must find the vertex has coordinate (h, k). h = -b / 2a  where:a = -1b = 23
h= -23  / -2  =  11.5 

 <span>x = 11.5   


</span>Substitute this value of x into eq1 to find y. y = 23 - xy = 23 - 11.5y = 11.5

<span>The two numbers that will give the largest product possible are 11.5 and 11.5.</span>

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BARSIC [14]
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Vladimir [108]

Answer:

So you would use the distance formula which is the square root of (x2-x1)^2 + (y2-y1).

Step-by-step explanation:

So it would be the square root of (-15-(-15)^2 + (6-1)^2

(-15-(15)^2 is the same thing as (-15+15)^2.

(-15+15)^2 is equal to 0^2 which is, 0.

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Radical 25 is equal to 5.

So, the final answer is 5.


3 0
4 years ago
The value of the fraction 3c+2/4 one less than the value of the fraction 5c-1/3<br><br> Solve for c
kifflom [539]

Answer:

<h3>c = 2</h3>

Step-by-step explanation:

The value of the fraction 3c+2/4 one less than the value of the fraction 5c-1/3 is expressed as;

(3c+2)/4 = (5c-1)/3 - 1

We are to calculate the value of c as shown;

(3c+2)/4 = (5c-1)/3 - 1

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Hence the value of c is 2

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