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3 years ago

9

you are standing on a peer 35 feet above the see water if you drop your hookon a fishing pole 38 feet deep under the water, how

far are you from your hook?

1 answer:

VashaNatasha [74]3 years ago

8 0

You are 73 feet away from the hook ?

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A number is greater than -4 and less than 9. what is the least possible integer value of this number?

Alex Ar [27]

10 is the answer ...

3 0

3 years ago

Read 2 more answers

balu736 [363]

Answer:

∠4 and ∠3

∠4 and ∠5

∠3 and ∠6

Step-by-step explanation:

A pair of angles is said to be supplementary when the 2 angles add up to give 180°.

Two right angles add up to give 180°. Also, if we have two angles on a straight line, their sum = 180°, according to the linear pair property.

Thus, since m< 3 is given as 90°, m<4 = 90°.

m<4 + m<3 = 180°.

Therefore, <4 and <3 are supplementary.

<4 and <5, <3 and <6 are both linear pairs, therefore they are also supplementary.

6 0

4 years ago

Can anyone please solve this question

DENIUS [597]

The first number is 27 and the second number is 45 so the ratio would be 27;45

5 0

3 years ago

H(m)+42= need help with problem

kondaur [170]

It depends on H(m) what is it?

7 0

3 years ago

A welder drops a piece of red-hot steel on the floor. The initial temperature of the steel is 2,500 degrees Fahrenheit. The ambi

sergey [27]

Answer: After 18.05 minutes, the temperature of steel becomes 100 degrees.

Step-by-step explanation:

Since we have given that

Initial temperature = 2500

At t = 0,

we get that

$f(t)=Ce^{-kt}+80\\\\2500=C+80\\\\2500-80=C\\\\2420=C$

After 2 minutes, the temperature of the steel is 1500 degrees.

so, it becomes,

$1500=2420e^{-2k}+80\\\\1500-80=2420e^{-2k}\\\\\dfrac{1420}{2420}=e^{-2k}\\\\0.587=e^{-2k}\\\\\ln 0.587=-2k\\\\-0.533=-2k\\\\k=\dfrac{0.533}{2}\\\\k=0.266$

So, We need to find the number of minutes when the temperature of steel would be 100 degrees.

So, it becomes,

$100=2420e^{-0.266t}+80\\\\100-80=2420e^{-0.266t}\\\\20=2420e^{-0.266t}\\\\\dfrac{20}{2420}=e^{-0.266t}\\\\\ln \dfrac{20}{2420}=-0.266t\\\\-4.8=-0.266t\\\\t=\dfrac{4.8}{0.266}\\\\t=18.05$

Hence, after 18.05 minutes, the temperature of steel becomes 100 degrees.

7 0

3 years ago