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olya-2409 [2.1K]
3 years ago
9

The points earned by each choir team during the All-State Competition are as follows:

Mathematics
1 answer:
gavmur [86]3 years ago
8 0
130.1 because 1 rounds down to 0 it isn't over 5
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(-8x-3)- -5<br> i need work shown i don't know how to do this one
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The answer for this problem is -8x+2  

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How do I find the derivative of 2(f(x)+g(x))?
kramer
\bf 2[f(x)+g(x)]\implies 2f(x)+2g(x)\implies 2\cfrac{df}{dx}+2\cfrac{dg}{dx}\\\\&#10;-------------------------------\\\\&#10;\cfrac{1}{2}\left[ f(x)\cdot g(x)  \right]\implies \cfrac{1}{2}\left[ \stackrel{product~rule}{\cfrac{df}{dx}\cdot g(x)+f(x)\cdot \cfrac{dg}{dx}} \right]&#10;\\\\\\&#10;\cfrac{1}{2}\cdot \cfrac{df}{dx}\cdot g(x)+\cfrac{1}{2}\cdot \cfrac{dg}{dx}f(x)
8 0
4 years ago
Read 2 more answers
In 1990, the profit of the Gamma company was $11.900,848. Each year after 1990profits fell by \$48,263 on average Construct a li
Marina86 [1]

Answer:

$10452958

Step-by-step explanation:

Initial profit = $11900848

Fall rate= $48263 per year

Equation:

  • P(x)= 11900848 - (x-1990)*48263,

where P(x)= profit at year of x, and 1990<x<2020

  • P(2020)= 11900848- 30*48263= $10452958
4 0
4 years ago
Can anyone answer this question for me and also if you’re able to give me the explanation on how to solve it also. PLEASE.
photoshop1234 [79]

<u>Answer</u><u>:</u>

<u> </u><u>First</u><u> </u><u>option=$13950 is correct.</u>

<u>Why</u><u>?</u>

<u>Total</u><u> </u><u>other</u><u> </u><u>cost</u><u> </u><u>=</u><u>$</u><u>1</u><u>5</u><u>5</u><u>0</u><u>0</u>

<u>1</u><u>0</u><u>%</u><u> </u><u>saving</u><u> </u><u>on</u><u> </u><u>other</u><u> </u><u>cost</u>

=10% × $15500

=$1550

<u>So total cost target on other cost for next month</u>

=$15500-$1550

=$13950

8 0
3 years ago
State whether the decay is linear or​ exponential, and answer the associated question. The value of a car is decreasing by 9​% p
Sunny_sXe [5.5K]

Answer:

  • Exponential
  • A(2)=$9109.10

Step-by-step explanation:

Since the value of the car decreases by a common factor each year, the decay is exponential.

An exponential decay function is of the form

A(t)=A_0(1-r)^t$ where:\\Initial Value, A_0=\$11,000\\$Decay Factor, r=9%=0.09

Therefore, the function modeling the car's decay is:

A(t)=11000(1-0.09)^t

We want to determine the car's value in two years.

When t=2

A(2)=11000(1-0.09)^2\\A(2)=\$9109.10

The value of the car in 2 years will be A(t)=$9109.10

7 0
3 years ago
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