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PolarNik [594]
3 years ago
9

Please help me, i dont understand ​

Mathematics
1 answer:
Kitty [74]3 years ago
5 0

Answer:

OK so we can see that when x increases y does too. The answer is C

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Please HURRY, MAJOR, brainiest if correct
Wewaii [24]

Answer: The answer is B.

7 0
3 years ago
Let f(x)=3x+1 and g(x)=x^2+xAfter simplifying (fg)(x)
natima [27]
(fg)(x)\text{ = }3x^3+4x^2+x

Here, we want to find the product of the two given functions

Mathematically;

\begin{gathered} (fg)(x)\text{ = f(x) }\times\text{ g(x)} \\  \\ =(3x+1)(x^2+x) \\ =3x^3+3x^2+x^2+x \\ =3x^3+4x^2+x \end{gathered}

5 0
1 year ago
Which graph of f(x) satisfies the conditions lim f(x) = -4 and lim f(x) = 0?<br> X2-<br> X-2+<br> Y
Mkey [24]

The graph of f(x) satisfies the conditions lim f(x) = -4 and lim f(x) = 0 is the graph attached.

<h3>What is one-sided limit for function?</h3>

It should be noted that the limit from one side is simply when the side of the functions is used with respect to the point of interest.

For this graph, the point x = 2 on the left from the point x = 2 lies a ray. The prediction here is that the value of function on x = 2 us the value that the line gives for y.

Therefore, the graph of f(x) satisfies the conditions lim f(x) = -4 and lim f(x) = 0 is attached.

Learn more about graph on:

brainly.com/question/19040584

#SPJ1

5 0
2 years ago
I need help finding the missing side length with the answer in radicals in the simplest form.
AlekseyPX

Answer:

C

Step-by-step explanation:

There’s nothing hard with this

You need to know special right triangles

This is a 30,60, 90 triangle

We automatically know becuase theres. Right angle (90) and a 60 degree angle

now the formula is the smallest side is (n) {I’m using N becuase theres already an X) or in this case, 6

The hypotenuse, the one directly above the 2nd biggest side, or the diagnoal side is 2n or (12). Now we know what X is in this situation which is 12. So that narrows it to 2 answers

Now the side on the bottom of the hypotenuse, the second biggest side is used in the formula N\sqrt{3}. So we know what N is in the beginning, 6 so we just plug that in and well get C. Attached is a photo on q 30, 60, 90 special right triangle

4 0
3 years ago
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
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