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4 years ago

Simplify. y^5 ÷ y^3 • y^2

Mathematics

1 answer:

kykrilka [37]4 years ago

4 0

Answer:

y^4

Step-by-step explanation:

Exponential laws state that you subtract the exponents when dividing (5-3=2) and you add when multiplying (2x2)

giving you y^4

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C) Ther is one outliner , indicating an abnormally large number of books were rented out on that day

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3 years ago

Read 2 more answers

What is 1.3 repeating in fraction

Rudiy27

1 $\frac{3}{10}$

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3 years ago

Select from the drop-down menus to correctly identify whether the given operation is closed or not closed with respect to each s

Tatiana [17]

Answer:

Real numbers are "closed" under multiplication

Irrational numbers are "not closed" under division

Integers are "closed" under subtraction

Positive ration numbers are "closed"

Hope this helps! :)

6 0

3 years ago

4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25

jarptica [38.1K]

Answer with explanation:

$\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}$

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

$=e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}$

Multiplying both sides by Integrating Factor

$x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)$

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

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3 years ago

The distance from Joshua's house to the mall is 3.5 miles. The distance from Meg's house to the mall is 19,000 feet. Who lives c

damaskus [11]

Answer:

i think its Joshua

7 0

3 years ago