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MissTica
3 years ago
13

Shelley’s pet food store sold one customer 5 peanut butter biscuits for $3. She sold another customer 7 beef treats for $4.20.

Mathematics
2 answers:
tatuchka [14]3 years ago
3 0

Answer:

I think that is the answer to this math work 5 × 3= $15 7 × $4.20=$29.40 All together it will be $44.40

garik1379 [7]3 years ago
3 0

Answer:

Its 21 on edenuity

Step-by-step explanation:

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96 = 2 x 2 x 2 x 2 x 2 x 3 or 2⁵ x 3.

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3 years ago
At a TV.repair shop, the amount charged for labor depends on the time the
Pepsi [2]

Answer:

A. Amount(hours worked)  

Step-by-step explanation:

Function notation is a way of converting a written description of a function to a concise form that is easy to read.

It is another way of representing the y-value in a function, y = ƒ(something)

Let's convert the word expression to function notation:

  • "The amount charged for labour depends on the time the repair technician works."
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  • "The amount is a function of the hours worked."
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6 0
3 years ago
Somebody help me please ASAP!!!!!!!!!!!!!!
mixer [17]

Answer:

V=-15

Step-by-step explanation:

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7 0
3 years ago
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Vitek1552 [10]

Answer:

11.27

Step-by-step explanation:

8 0
3 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
mina [271]

Answer:

The tip of the man shadow moves at the rate of \frac{20}{3} ft.sec

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

\frac{y - x}{y} = \frac{6}{15}

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = \frac{15x}{9\\} y = \frac{5x}{3}

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt} ----(1)

We are given \frac{dx}{dt} = 4 ft/sec. Plug in the equation (1), we get

\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0
3 years ago
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