Answer:
The small balloon bouquet uses 7 balloons and the large one uses
18 balloons.
Step-by-step explanation:
Let's say that small balloon bouquets are S and large balloon bouquets are L. For the graduation party the employee assembled 6 small bouquets and 6 large bouquets, the total number of balloon used is 150. To put the sentence into an equation will be:
6S + 6L= 150
S+L= 25 ----> 1st equation
For Father's Day, the employee uses 6 small bouquet and 1 large bouquet, the total number of balloons used is 60. The equation will be:
6S + 1L= 60
1L= 60- 6S ----> 2nd equation
We can solve the number of small balloon bouquet by substitute the 2nd equation into 1st. The calculation will be:
S+L = 25
S+ (60-6S)= 25
-5S= 25-60
-5S= -35
S= -35/-5
S=7
Then we can find L by substitute S value to 1st or 2nd equation.
S+L=25
7+L=25
L=18
Answer:
x+ x×3%×11/2=19513.75 considering 3% interest per year for 5 and a half years
x=8375
Step-by-step explanation:
x×233/200=19513.75
x=1951375/233
x=8375
Answer: <em>x</em>∈(5,∞)
Step-by-step explanation:
x-7>-2=(x-7)+7>-2+7=<em>x</em>∈(5,∞)
To solve we need to group all the variables on one side, and all the constants on the other side.
Answer:
you could just count them