Answer:
6546 students would need to be sampled.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the z-score that has a p-value of
.
The margin of error is:

The dean randomly selects 200 students and finds that 118 of them are receiving financial aid.
This means that 
90% confidence level
So
, z is the value of Z that has a p-value of
, so
.
If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?
n students would need to be sampled, and n is found when M = 0.01. So






Rounding up:
6546 students would need to be sampled.
Answer:
x=-1
Step-by-step explanation:
By adding the bottom lines you can get
2x+11 = x+10
Simplifying this gets you
x=-1
Answer:
Step-by-step explanation:
5/8 + 3/5 =
25/40 + 24/40 =
49/40 = 1 9/40
its greater then 1
-371 7/24
From quizlet made from balletskye20 with 16 terms
D (-4 , -1)
relflected over x-axis= (4 , 1)
180 degrees= (-4 , -1)