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romanna [79]
4 years ago
8

What is the greatest common factor of 20, 45x?

Mathematics
1 answer:
mote1985 [20]4 years ago
7 0
The greatest common factor of 20 and 45x is 5
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Find the area of this polygon (composite figure). Remember your units.
Andre45 [30]
So u can see a rectangle and a triangle
Area of the rectangle is 7 x 12 = 84ft
Area of the triangle= base x height divided by 2
So 6 x 12 = 72. 72/2 = 36ft
Then u add both areas
36 + 84 = 120ft
Hope this helps!
6 0
3 years ago
Read 2 more answers
A video game designer is modeling a tower that is 320 ft high and 260ft wide. She creates a model so that the similarity ratio o
maksim [4K]
H = Tower Height = 320
W = Tower Width = 260
h = Model Height
w = Model Width

h = (1/500) * H = (1/500) * 320 = .64 feet
w = (1/500) * W = (1/500) * 260 = .52 feet

Now, we need to convert these measurements to inches.

There are 12 inches per foot.

Let x = height in inches and y = width in inches

The ratio below compares feet to inches

x / h = 12 in / 1 ft
y / w = 12 in / 1 ft

Plug in h and w, cross multiply, and solve for x and y, respectively.

x / .64 = 12 / 1
1 * x = .64 * 12
x = 7.68 in

y / .52 = 12 in / 1 ft
1 * y = .52 * 12
y = 6.24 in



 
5 0
3 years ago
Drag and drop each pair of lines into the correct category to indicate whether the pair of lines are parallel, perpendicular, or
zhenek [66]

parallel:

y=5x-1 ; 10x-2y=12

perpendicular:

3x-5y=-1 ; 3y=-5x+2

6y=4x+1 ; 12x+8y=12

neither:

1/7x+y=7 ; y=-7x

x-6y=12 ; x+4

6 0
3 years ago
At the beginning of this month, the balance of Nelson's checking account was $856.23. So far this month, he has received a paych
kari74 [83]
$1,619.30

Hope this helps<3
6 0
3 years ago
Read 2 more answers
In the relationship shown by the data linear ? If so , model the data with an equation A. The relationship is not linear B. The
dybincka [34]

Let's take two points so that we can get the equation of the line which goes through those points. P1 (-9, -2), P2 (3, -17):

m=\frac{y_2-y_1}{x_2-x_1}=\frac{-17-(-2)}{3-(-9)}=\frac{-17+2}{3+9}=-\frac{15}{12}=-\frac{5}{4}\begin{gathered} y-y_1=m(x-x_1) \\ y-(-2)=-\frac{5}{4}\cdot(x-(-9)) \\ y+2=-\frac{5}{4}\cdot(x+9)_{} \\ y=-\frac{5}{4}x-\frac{45}{9}-2 \\ y=-\frac{5}{4}x-7 \\ f(x)=-\frac{5}{4}x-7 \end{gathered}

So, y is the line which goes through the first and last points of the chart.

To proof that the rest of points go through the line as well, we will evalute each point

\begin{gathered} f(-5)=-\frac{5}{4}\cdot(-5)-7=\frac{25}{4}-7=-\frac{3}{4}\ne-7 \\ f(-1)=-\frac{5}{4}(-1)-7=\frac{5}{4}-7=-\frac{23}{4}\ne-12 \end{gathered}

Since the evaluation of these points don't correspond to the values of the chart we can assure that the relationship is not linear

7 0
2 years ago
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