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Akimi4 [234]
3 years ago
7

A rectangle that is twice as long as it is wide forms the base of a rectangular pyramid that is 60cm high. If the volume of the

pyramid is 4000 cm cubed, what are the dimensions of the rectangle?
Full show working out ty;)
Mathematics
1 answer:
Vitek1552 [10]3 years ago
3 0

Answer:

10 * 20 cm.

Step-by-step explanation:

Let the width of the base = x, then it's length is 2x cm  and the area = 2x^2 cm^2.

Volume = 1/3 * height * area of the base

4000 = 1/3 * 60 * 2x^2

2x^2 = 4000 / (1/3 * 60)

2x^2 = 4000 / 20 = 200

x^2 = 200/2 = 100 cm.

x = 10 cm.

So the dimension of the rectangle =  10 * 20 cm.

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Determine which postulate can be used to prove that the triangles are congruent. If it is not possible to prove congruence, writ
irakobra [83]

Answer:

The triangles are congruent by

SSS

Step-by-step explanation:

Given:

First Label the Diagram:

AB ≅ CD

AD ≅ BC

To Prove:

Δ ABC ≅ Δ CDA

Proof:

In  Δ ABC and Δ CDA

AB ≅ CD     ....……….{Given}

BC ≅ DA     …………..{Given}

AC ≅ AC     ……….{Reflexive Property}

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8 0
3 years ago
The angles of a triangle are 80º, 2x + 2º, and 5xº. What is the value of x?
Gekata [30.6K]
Since the sum of the angles of a triangle = 180°

Then  <span>80º + (2x + 2)º + 5xº  = 180</span>°
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                                    (7x)° = 180° - 82°
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                                    ∴  x   = 14
7 0
3 years ago
Sally buys a hang bag. There was a discaount of 35percent . If Sally paid $56.80 what was the original price?
Ksju [112]
Discount = 35%
Percentage after discount = 100% - 35% = 65%

65% = $56.80
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Answer: The original price is $87.38
4 0
2 years ago
Read 2 more answers
What is the value of 34 + 3.5(−44÷2)? <br><br>a.−111 <br><br>b.−43 <br><br>c.43 <br><br>d.111
mart [117]

Answer:

b

Step-by-step explanation:

-44÷2=-22

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5 0
2 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)]     since  [cos²(6θ) + sin²(6θ)] = 1

6 0
3 years ago
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