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Grace [21]
4 years ago
7

Simplify (6x-5)-(3x-2)

Mathematics
2 answers:
Sveta_85 [38]4 years ago
4 0
(6x - 5) - (3x - 2)
Distribute (multiply) the negative sign to (3x - 2).

6x - 5 - 3x + 2
Combine like terms; 6x - 3x and -5 + 2.

3x - 3 is your answer.
lisabon 2012 [21]4 years ago
4 0
I would think (6x-5)-(3x-2)= -24
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jasenka [17]

Answer:

1. The correct option B.

2.The correct option A.

Step-by-step explanation:

The given function is

f(d)=-0.6d^2+5.4d+0.8

Where f(d) is the height of the ball at horizontal distance d.

Put f(d)=0, to find the distance where the ball touch the ground.

0=-0.6d^2+5.4d+0.8

Quadratic formula:

d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Using the quadratic formula we get

d=\frac{-5.4\pm \sqrt{(5.4)^2-4(-0.6)(0.8)}}{2(-0.6)}

d=-0.146,9.146

Therefore the ball is in air between d=-0.146 to d=9.146.

The distance can not be negative, therefore the ball remains in the air between d=0 to d=9.146.

9.146\approx 9.15

Therefore the correct option is B.

2.

The given equation is

y=(x-1)^2+1                 .... (1)

The standard form of parabola is

y=a(x-h)^2+h             .... (2)

Where, a is constant and (h,k) is vertex.

On comparing (1) and (2), we get

a=1

h=1

k=1

Since the value of a is positive, therefore it is an upward parabola. The vertex of the parabola is (1,1).

Put x=0 in the given equation.

y=(0-1)^2+1

y=1+1=2

Therefore the y-intercept is (0,2) and option A is correct.

8 0
3 years ago
Given the expression,f(X)=x-3 / x^2-25 , choose the correct x coordinate of the x-intercept.
Licemer1 [7]
The x intercept(s) occur  when f(x) = 0

so we have (x - 3)( x^2 - 25)  = 0

So x - 3 = zero  and  x = therefore = 3.

The answer is the third choice 3
8 0
4 years ago
Which number is least 145. 155 or 144.809
GREYUIT [131]

145.555 is the least

7 0
3 years ago
Read 2 more answers
What are the zeros (x-intercepts) of the function y - 2x2 +7x+3?
xeze [42]

Step-by-step explanation:

b+/-(√b^2-4ac)/2a

7+/-(√7^2-4(2)(3)/2(2)

=-3 or =-1/2

8 0
3 years ago
Simplify 9x^8 divided by 12x^5.
Dmitry_Shevchenko [17]
Ok, so rembmer some basica exponential rules and some fraction rules

(ab)/(cd)=(a/c)(b/d)
and
\frac{x^n}{x^m} =x^{n_m}

so
\frac{9x^8}{12x^5}=( \frac{9}{12} )(  \frac{x^8}{x^5} )=( \frac{3}{4} )(  x^{8-5} )= ( \frac{3}{4} )(  x^{3} )=  \frac{3x^3}{4}
6 0
3 years ago
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