<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
Option A
Step-by-step explanation:
By using the definition of an exterior angle of a triangle,
"Measure of the exterior angle of a triangle is equal to the sum of measures of the opposite interior angles"
m∠STP = m∠SWT + m∠STW
Substitute the measures of the angles from the picture attached,
15x = (7x + 1) + (7x + 6)
15x = (7x + 7x) + (1 + 6)
15x = 14x + 7
15x - 14x = 7
x = 7
Therefore, Option A will be the correct option.
Using the asymptote concept, the function with a vertical asymptote at x = 3 and an horizontal asymptote at
is given by:

<h3>What are the asymptotes of a function f(x)?</h3>
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
The vertical asymptote at x = 3 means that x = 3 is a root of the denominator, hence:

The horizontal asymptote at y = -1/2 means that:

Which happens if
, hence the function is:

More can be learned about asymptotes at brainly.com/question/16948935
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Answer:
The total number of ways are 168.
Step-by-step explanation:
Consider the provided information.
There are 7 junior and 3 senior coders in her group.
The first project can be written by any of the coders. The second project must be written by a senior person and the third project must be written by a junior person.
For second project we have 3 choices and for third project we have 7 choices.
Now there are 2 possible case:
Case I: If first and second coder is senior, then the total number of ways are:

Case II: If first and third coder is junior, then the total number of ways are:

Hence, the total number of ways are: 42+126=168