The radius of the Outer circle (with r₂) is 6 and the radius of the inner circle (with r₁) is 2. When objects are similar, they have a proportional relationship. If we take the outer circle and squeeze by one third, we get a radius of 6 x 1/3 = 2. On the other hand, if we start with the inner circle and stretch it by 3, we get a radius of 2 x 3 = 6.
Thus, to make r₂ similar, we use a scale factor of 1/3. The third choice is best.
Answer:
$60
Step-by-step explanation:
12/8 = x/40
40(12/8) = x
60 = x
1. Find the centre of the circle or the midpoint of the two numbers
(6-6/2}, (-2+6/2)
(0, 2)
2. Find radius using the distance formula
√<span>(6 - 2)² + (-6 - 0)²
</span>√4² + (-6)²
√16 + 36
√52
r = 7.21
3. Plug in
x² + (y - 2)² = 52
So it is option D 99% sure
The point of intersection is at (0,2)