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MAXImum [283]
3 years ago
5

How do I solve 4cos^2 x -1=0

Mathematics
2 answers:
Gala2k [10]3 years ago
7 0

Answer:

pi/3? 2pi/3?

Step-by-step explanation:

tekilochka [14]3 years ago
5 0
(cosx)^{2} = 1/4 <=> cosx = +1/2 or cosx = -1/2;
cosx = +1/2 => x = +π/3 + 2kπ, where k is an integer or x = -π/3 + 2kπ, where k is an integer;
cosx = -1/2 => x = +2π/3 + 2kπ, where k is an integer or x = -2π/3 + 2kπ, where k is an integer;
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