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3 years ago

The counting numbers, together with 0, are called the _ _ _ _ _ numbers.

Mathematics

1 answer:

german3 years ago

4 0

Answer:

Whole numbers

hope this helps!

Step-by-step explanation:

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Need help with this geometry question, solving for x and please explain the formula for this

Alborosie

Alright, so what we can take as a given is that arcDE/2= ∠CDE=2x+20 since the arc corresponding to the angle is 2*the angle. To solve for arcDE, we multiply both sides by 2 to get 2(2x+20)=4x+40=arcDE. Since the arcs in a circle add up to 360 degrees and we only have -20+30x and arcDE, we have -20+40+4x+30x=360 using the associative property. Simplifying, we get 20+34x=340. Subtracting 20 from both sides, we get 340=34x. Next, we can divide both sides by 34 to get 10=x.

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3 years ago

Find the volume (don't forget your UNITS) *

Evgesh-ka [11]

The vloume is 5*7*2=70 inch

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3 years ago

Read 2 more answers

Use the Associative Property of Addition to write an expression equivalent to r+ (h+t). r+ (h+t) = Enter your answer in the answ

svlad2 [7]

Answer:

Associative propertry of addition.

Step-by-step explanation:

The associative property of addition states that:

$a+(b+c) = (a+b)+c$

It states that we can add numbers regardless of the groups. The sum does not change irrespective of how the addends are grouped.

We are given the expression:

$r + (h + t)$

It can be written as:

$(r+h) + t$

It can also be written as:

$r + (h+t) = (r+t) + h = (h+t)+r = h + (t+r)$

Whatever maybe the arrangement of r, h and t, their sum will always be equal. We can regroup them in many ways but the sum remains the same.

4 0

3 years ago

The lengths of two sides of a triangle are shown below:

oksano4ka [1.4K]

Part A

$3x^2 -2x-1+9x+2x^2 -3=\boxed{5x^2 + 7x-4}$

Part B

$(5x^3 +4x^2 - x-3)-(5x^2 + 7x-4)=\boxed{5x^3 - x^2 - 8x+1}$

Part C

No, because although they provide examples for specific polynomials being closed under addition and subtraction, there is a loss of generality.

6 0

2 years ago

The point (5/13, y) in the fourth quadrant corresponds to angle theta on the unit circle. Find sec theta and cot theta

VikaD [51]

Cos (theta) = $\frac{5}{13}$ sec (theta) = $\frac{1}{cos(theta)} = \frac{1}{ \frac{5}{13} }= \frac{13}{5}$ sin(theta)= $\sqrt{1- cos^{2}(theta) } = \sqrt{1 - \frac{25}{169} } = \sqrt{ \frac{144}{169} }=- \frac{12}{13}$ cot(theta)= $\frac{cos(theta)}{sin(theta}= \frac{ \frac{5}{13} }{ \frac{-12}{13} }= \frac{-5}{12}$

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3 years ago