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Leni [432]
4 years ago
9

Write the following decimal in expanded notation 56.78​

Mathematics
1 answer:
Fudgin [204]4 years ago
4 0

Answer:

its the same answer 56.78

Step-by-step explanation:

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Which graph represents a function?
vivado [14]

Answer:

c

Step-by-step explanation:

7 0
3 years ago
Find the missing angle.
hammer [34]

Answer:

Linear pair angle of 40 is

=180-40

=140

If, the two rays are parallel

Therefore, the two rays are parallel and the straight line is transversal

Therefore, (?) angle =140 corrosponding angle

Your answer is 140

4 0
3 years ago
Carol is standing 8 feet from a lamppost. The angle of elevation from her eyes to the top of the lamppost is 20o, and the angle
kupik [55]

Answer:

Height of the lamppost = 5.602 ft + 2.912 ft = 8.514 ft

Step-by-step explanation:

The illustration form a triangle that can be demarcated into 2 right angle triangle. One triangle representing depression triangle and the other elevation triangle.

Depression triangle

The opposite side of the triangle formed is the length of the pole from the base to the horizontal line of sight. Therefore,

using tangential ratio

tan 35° = opposite/adjacent

tan 35° = a/8

cross multiply

a = 8 tan 35°

a = 8 × 0.70020753821

a = 5.60166030568

a = 5.602 ft

Elevation triangle

The opposite side of this right angle triangle represent the length from the horizontal line of sight to the top of the lamppost.

tan 20° = opposite/adjacent

tan 20° = b/8

cross multiply

b = 8 tan 20°

b = 8 × 0.36397023426

b = 2.91176187413

b = 2.912 ft

Height of the lamppost = 5.602 ft + 2.912 ft = 8.514 ft

8 0
3 years ago
Help, please. <br> Find the value of the blue dot on the number line
REY [17]
-19
Explanation: they go back in intervals of -3
6 0
3 years ago
The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?
MaRussiya [10]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}

~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill

3 0
1 year ago
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