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Nadusha1986 [10]
3 years ago
8

How many solutions does this system have?

Mathematics
2 answers:
Julli [10]3 years ago
6 0

Answer:

one solution

Step-by-step explanation:

* Lets start to solve the question

- The 1st equation x - y = -4

- The 2nd equation 3x + y = 8

- We will use the elimination method to solve this system of equation

∵ x - y = -4 ⇒ (1)

∵ 3x + y = 8 ⇒ (2)

- Add the two equation (1) and (2) to eliminate y

∴ x + 3x = -4 + 8

∴ 4x = 4

- Divide both sides by 4

∴ x = 1

- Substitute the value of x in equation (1) or equation (2) to find

  the value of y

- We will use equation (1)

∴ 1 - y = -4

Subtract 1 from both sides

∴ -y = -5

- Divide both sides by -1

∴ y = 5

∴ The solution is (1 , 5)

* The system has one solution

Ann [662]3 years ago
5 0

Answer:  ONE

<u>Step-by-step explanation:</u>

I am going to use elimination method to solve for x. Since they already have an opposite coefficient for y, I can add the two equations to eliminate y.

 x - y = -4    

<u>3x + y = 8  </u>

4x       = 4

 x       =\dfrac{4}{4}

 x       = 1

Substitute x with 1 in either of the equations to solve for y:

3(1) + y = 8

 3  + y = 8

        y = 5

Therefore, there is ONE solution, which is (1, 5).

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