C because you have to do 50÷2=25 and 40÷2=20 and 20-25=5
Answer:
an = -8 +3(n-1)
an = -11 +3n
f(n) = -11 +3n
Step-by-step explanation:
–8, –5, –2, 1, 4, ...
This is an arithmetic sequence.
We are increasing by 3 each time
-8 +3 = -5
-5+3 = -2
-2 +3 = 1
The common difference is 3
The formula for an arithmetic sequence is
an = a1 +d (n-1)
an = -8 +3(n-1)
an = -8 +3n -3
an = -11 +3n
The nth term is -11 +3n
f(n) = -11 +3n
Hi!
<h3>Expanded form is when we multiply each of the digits by how many 0s they have. </h3>
So 253 is (2 x 100) + (5 x 10) + (3 x 1).
17,000
400
9
(<u>17 x 10,000) + (4 x 100) + (9 x 1)</u>
<h2>The answer is C) (<u>17 x 10,000) + (4 x 100) + (9 x 1)</u> (which equals 17,409)</h2>
Hope this helps! :)
-Peredhel
Put 65 over 100 so it's a fraction and simplify from there i think
Answer:
![$\[x^2 + 22x + 121\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20121%5C%5D%24)
Step-by-step explanation:
Given
![$\[x^2 + 22x + \underline{~~~~}.\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20%5Cunderline%7B~~~~%7D.%5C%5D%24)
Required
Fill in the gap
Represent the blank with k
![$\[x^2 + 22x + k\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20k%5C%5D%24)
Solving for k...
To do this, we start by getting the coefficient of x
Coefficient of x = 22
<em />
Divide the coefficient by 2


Take the square of this result, to give k


Substitute 121 for k
![$\[x^2 + 22x + 121\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20121%5C%5D%24)
The expression can be factorized as follows;




<em>Hence, the quadratic expression is </em>
<em></em>