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SashulF [63]
3 years ago
12

Jayden wants to lay sod on his front yard and on half of his back yard. His front yard has a length of 50 feet and a width of 80

feet. His back yard has a length of 10 feet and a width of 40 feet. How many square feet of sod does Jayden need to purchase?
Mathematics
1 answer:
Svetlanka [38]3 years ago
7 0
Its an area equation. Area is length times width.

So to start, he needs 50x80 square feet in his front yard, BUT THAT IS ONLY HALF OF THE PROBLEM. For the front yard he needs 4000 sq. feet. For the back, it is different. He needs 10x40÷2. To first simplify, we do the multiplication. This comes to 400÷2. then it is simply 200.

Now for the easy part. Take the 4000 and add 200. Answer? 4,200.
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2 years ago
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Taya2010 [7]

Answer:

x_{1} = -\frac{1}{3} +\sqrt{2} ; x_{2} = -\frac{1}{3}-\sqrt{2}

Step-by-step explanation:


9x² + 6x – 17 = 0

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x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

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x = \frac{-6\pm\sqrt{6^2 - 4\times 9 \times(-17)}}{2\times 9}

x = \frac{-6\pm\sqrt{36+36\times17}}{18}

x = \frac{-6\pm\sqrt{36(1+17)}}{18}

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x = \frac{-1\pm \sqrt{9\times2}}{3}

x = \frac{-1\pm 3\sqrt{2}}{3}

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The graph below shows the roots at x₁ =1.081 and x₂ = -1.748.

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ollegr [7]
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To find the answer, subtract

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alukav5142 [94]

Answer:

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3 years ago
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