All categories

3 years ago

3x-4y=2 what is the coordinate of the x intercept in this equation

Mathematics

1 answer:

Lunna [17]3 years ago

7 0

Plug in zero for x to find the x intercept. So 3(0)-4y=2.
=-4y=2. Y=-1/2. X int. = (0,-1/2)

You might be interested in

A closed-top cylindrical container is to have a volume of 250 in2. 250 , in squared , . What dimensions (radius and height) will

miv72 [106K]

Answer:

radius r = 3.414 in

height h = 6.8275 in

Step-by-step explanation:

From the information given:

The volume V of a closed cylindrical container with its surface area can be expressed as follows:

$V = \pi r^2 h$

$S = 2 \pi rh + 2 \pi r^2$

Given that Volume V = 250 in²

Then;

$\pi r^2h = 250 \\ \\ h = \dfrac{250}{\pi r^2}$

We also know that the cylinder contains top and bottom circle and the area is equal to πr²,

Hence, if we incorporate these areas in the total area of the cylinder.

Then;

$S = 2\pi r h + 2 \pi r ^2$

$S = 2\pi r (\dfrac{250}{\pi r^2}) + 2 \pi r ^2$

$S = \dfrac{500}{r} + 2 \pi r ^2$

To find the minimum by determining the radius at which the surface by using the first-order derivative.

$S' = 0$

$- \dfrac{500}{r^2} + 4 \pi r = 0$

$r^3 = \dfrac{500 }{4 \pi}$

$r^3 = 39.789$

$r =\sqrt[3]{39.789}$

r = 3.414 in

Using the second-order derivative of S to determine the area is maximum or minimum at the radius, we have:

$S'' = - \dfrac{500(-2)}{r^3}+ 4 \pi$

$S'' = \dfrac{1000}{r^3}+ 4 \pi$

Thus, the minimum surface area will be used because the second-derivative shows that the area function is higher than zero.

Thus, from $h = \dfrac{250}{\pi r^2}$

$h = \dfrac{250}{\pi (3.414) ^2}$

h = 6.8275 in

7 0

3 years ago

C2 - 6c-5<br> Evaluate the expression when c = -2

vivado [14]

-2(2)-6(-2)-5
-4+12-5
Answer is 3

3 0

3 years ago

According to the general equation for conditional probability, if P(A, B) =4/7

Neko [114]

Answer:

$P(A|B) = \frac{32}{49}$

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(A|B) = \frac{P(A \cap B)}{P(B)}$

In which

P(A|B) is the probability of event A happening, given that B happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(B) is the probability of B happening.

We have that:

$P(A \cap B) = \frac{4}{7}, P(B) = \frac{7}{8}$

$P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{\frac{4}{7}}{\frac{7}{8}} = \frac{4}{7}*\frac{8}{7} = \frac{32}{49}$

Then

$P(A|B) = \frac{32}{49}$

8 0

3 years ago

Use the Change of Base Formula to evaluate log3 48. Then convert log3 48 to a logarithm in base 5. Round to the nearest thousand

Alex

Answer:

I'm sorry I don't know this one

8 0

2 years ago

Which value of x is in the solution set of the following inequality?

andreyandreev [35.5K]

Answer:

C. 1

Step-by-step explanation:

Multiply every answer until you get an answer more than 6, and in this case it was C

4 0

3 years ago