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3 years ago

Let f(x) = x^2-6 and g(x) =10x . Find (g ° f)(x)

Mathematics

2 answers:

patriot [66]3 years ago

8 0

Answer:

10x^2-60

Step-by-step explanation:

(G o F)(x) is the same as g(f(x)). We know that f(x)=x^2-6. So now you have to find g(x^2-6). To solve for that plug in x^2-6 in for x in the original equation for g(x). You get 10(x^2-6) or 10x^2-60

balu736 [363]3 years ago

6 0

Answer:

$(g \circ f)(x)=10x^2-60$

Answer: $10x^2-60$

Step-by-step explanation:

$(g \circ f)(x)=g(f(x))$

Replace $f(x)$ with $x^2-6$ .

This gives us:

$(g \circ f)(x)=g(f(x))$

$(g \circ f)(x)=g(x^2-6)$

This means to replace the old input variable with new input, $(x^2-6)$ .

Let's do that:

$(g \circ f)(x)=10(x^2-6)$

They probably want you to distribute:

$(g \circ f)(x)=10x^2-60$

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superstore and cheap store are two supermarkets that sell boxes of the same type of cereal each supermarket has a special offer

Lena [83]

Answer:

Step-by-step explanation:

Cheapstore:

500p÷10=50p×2=100p or £1

£4=600g

Superstore:

600g÷10=60g×3=180g+600g

£5=780g

600÷4=150g per pound

780÷5=156g per pound

The box from Superstore is best value

8 0

3 years ago

Use a Double- or Half-Angle Formula to solve the equation in the interval [0, 2π). (Enter your answers as a comma-separated list

lara31 [8.8K]

Sin(2θ)+sin(θ)=0
use double angle formula: sin(2θ)=2sin(θ)cos(θ).
=>
2sin(θ)cos(θ)+sin(θ)=0
factor out sin(θ)
sin(θ)(2cos(θ)+1)=0
by the zero product property,
sin(θ)=0 ...........(a) or
(2cos(θ)+1)=0.....(b)
Solution to (a): θ=k(π)
solution to (b): θ=(2k+1)(π)+/-(π)/3
for k=integer

For [0,2π), this translates to:
{0, 2π/3,π,4π/3}

8 0

3 years ago

Helpeoepeoeoeo show work

alukav5142 [94]

IMPORTANT THIGNS TO REMEMBER:

Has 20 lb. dog food!
Gives dog 1 3/5 everyday!
Find how much eaten after 2 days!
Find how much is left!

ANSWER:

Dog has eaten 3 1/5 after 2 days!

There is 16 4/5 left in bag!

EXPLANATION:

Since she gives 1 3/5 to her dog everyday and their asking for 2 days you would multiply 1 3/5 × 2 OR add 1 3/5 + 1 3/5

Which would give you 3 1/5

So, the dog has eaten 3 1/5 lb. of dog food in 2 days.

However then, you would subtract 20 lb. - 3 1/5 lb. because there is 20 lb. dog food in all and the dog has eaten 3 1/5 of it. This would give you 16 4/5 lb.

Meaning there is 16 4/5 lb. left in the bag of dog food!

4 0

3 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

3 years ago

A butcher can cut through 390 pounds of beef a day and 48 pounds less of poultry. Find the absolute value of total beef and poul

shutvik [7]

Step-by-step explanation:

Clue: (I'm not giving the answer this is just clues) The word "absolute" helps you understand not to estimate so you want to get the RIGHT answer not the estimation.

6 0

3 years ago