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scoundrel [369]
3 years ago
9

Let f(x) = x^2-6 and g(x) =10x . Find (g ° f)(x)

Mathematics
2 answers:
patriot [66]3 years ago
8 0

Answer:

10x^2-60

Step-by-step explanation:

(G o F)(x) is the same as g(f(x)). We know that f(x)=x^2-6. So now you have to find g(x^2-6). To solve for that plug in x^2-6 in for x in the original equation for g(x). You get 10(x^2-6) or 10x^2-60

balu736 [363]3 years ago
6 0

Answer:

(g \circ f)(x)=10x^2-60

Answer:10x^2-60

Step-by-step explanation:

(g \circ f)(x)=g(f(x))

Replace f(x) with x^2-6.

This gives us:

(g \circ f)(x)=g(f(x))

(g \circ f)(x)=g(x^2-6)

This means to replace the old input variable with new input, (x^2-6).

Let's do that:

(g \circ f)(x)=10(x^2-6)

They probably want you to distribute:

(g \circ f)(x)=10x^2-60

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Answer:

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Step-by-step explanation:

-14x+28+6x=-44

-8x+28=-44

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Tems11 [23]

Answer:

As Per Provided Information

We have to use π = 3.14

Diameter of baseball is 3 inch

So, Radius of Baseball will be

  • Radius = Diameter/2

Radius = 3/2 inch

Radius = 1.5 inch

we have been asked to determine the surface area of given baseball .

<u>Using </u><u>Formulae </u>

<u>\boxed {\bf  \: Surface \:  Area_{(Baseball)} \:  = 4 \pi {r}^{2} }</u>

substituting the value and let's solve it

\longrightarrow\tt  \:Surface  \: Area_{(Baseball)} \:  = 4 \times 3.14 \times  {1.5}^{2}  \\  \\  \\ \longrightarrow\tt  \:Surface  \: Area_{(Baseball)} \:  = \: 4 \times 3.14 \times 2.25 \\  \\  \\ \longrightarrow\tt  \:Surface  \: Area_{(Baseball)} \:  = \: 12.56 \times 2.25 \\  \\  \\ \longrightarrow\tt  \:Surface  \: Area_{(Baseball)} \:  = \: 28.26 \:  {inch}^{2}

<u>Therefore</u><u>,</u>

  • <u>Surface</u><u> </u><u>Area </u><u>of</u><u> </u><u>baseball</u><u> </u><u>is </u><u>2</u><u>8</u><u>.</u><u>2</u><u>6</u><u> </u><u> </u><u>sq.</u><u> </u><u>inch</u><u> </u><u>.</u>

So, your answer is 28.26 sq.in

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