Point F is on line a, so it does represent Josiah's distance at a certain time. Also, point F is below line b, so it represents a distance that is less than Chana's distance. This is a distance-time graph problem.
<h3>
What is the proof for the above?</h3>
Recall that Josiah had a head start of 10 meters and he skates at 2 meters per second.
Since Y is the function that represents the distance in meters from the finished line, by observation, it is clear to see that all the factors that are related to his race are adequately represented in:
y = 10 + 2x
Where 10 is the head start in meters
2 is the rate at which he skates per second; and
x is the unknown amount of time in seconds.
Given that the point F sits over 25 seconds,
that is F(y) = 10 + 2 * 25
= 60 meters.
Hence, Point F is on line a, so it does represent Josiah's distance at exactly 25 seconds.
Learn more about distance-time graphs at:
brainly.com/question/4931057
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Answer:
domain- -2,2,3,5,5 range- -3,1,7,12,12
Step-by-step explanation:
depending on teacher, you may only put the two 5 and the two 12 once, but some teachers require both.
Look at the picture.
Corresponding angles:
∠1 and ∠5
∠2 and ∠6
∠3 and ∠7
∠4 and ∠8
<h3>Therefore your answer is ∠1 and ∠5</h3>
Answer:
16m tall
Step-by-step explanation:
Distance casted by the shadow = 32m = hypotenuse
Angle of elevation = 30 degrees
Required
Height of the building = opposite
Using the SOH CAH TOA identity
sin theta = opp/hyp
sin 30 = x/32
0.5 = x/32
x = 0.5 * 32
x = 16m
Hence the building is 16m tall