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3 years ago

Can someone help me really quick

Mathematics

1 answer:

Elena L [17]3 years ago

8 0

In your 30° - 60° - 90° triangle, the ratios of the sides are
.. PR : QR : PQ = 1 : √3 : 2

A) QR/PQ = (√3)/2 . . . . . TRUE

B) PR/PQ = 1/2, not (√3)/2 . . . . false

C) QR/PR = (√3)/1 . . . . . TRUE

D) PQ/PR = 2/1, not √3 . . . . . . .false

E) QR/PR (see C) . . . . . . . . . . .false

F) PQ/PR = 2/1 . . . . . . . .TRUE

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Work Out<br> 8^1/3 ÷ 5^-2

svp [43]

I believe the answer would be 50

explanation:

calculate
2 ÷ 5^-2

use negative power rule x^-a = 1/x^a
2 ÷ 1/5^2

simply 5^2 to 25
2 ÷ 1/25

use this rule a ÷ b/c = a • c/b
2 • 25

simplify
50

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3 years ago

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a student measured the temperature in degrees celsius for several winter days and recorded the data in a list find the average o

NemiM [27]

Answer:

Average = -1°C

Step-by-step explanation:

The data recorded is;

6, -7, -5, 5, -8, 3 (in °C)

Average = $\frac{6 - 7 - 5 + 5 - 8 + 3}{6}$ = -1°C

8 0

3 years ago

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What is 10 1/12 as a decimal

cricket20 [7]

Answer:

10.083

since 1/12 is .0833333333 and so on, it’s shortened

Step-by-step explanation:

8 0

3 years ago

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Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of

alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

- The standard form of the linear equation is Ax + BC = C, where

A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

parallel bases and which of them are the non-parallel bases

# The side RS

∵ $m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}$

# The side ST

∵ $m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}$

# The side TU

∵ $m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}$

# The side UR

∵ $m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}$

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

∵ The midpoint of RS = $(\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})$

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

midpoint of RS

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

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4 years ago

In what ways do you follow a healthy diet?

andrey2020 [161]

By eating healthy and constantly working out

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3 years ago

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