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belka [17]
3 years ago
13

2.300 in word form and the value of 3

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0
Two and Three Tenths is the word form of 2.300. 
The 3 holds the value of Three Tenths.
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Mindy and Troy combined ate 9 99 pieces of the wedding cake. Mindy ate 3 33 pieces of cake and Troy had 1 4 4 1 ​ start fraction
saul85 [17]

Answer:

(a)There are 24 cakes in total

(b)There are 15 pieces of cakes left

Step-by-step explanation:

Let the total cakes=x

Let number of cakes eaten by Mindy=m

Let number of cakes eaten by Troy=t

Now:

m=3

Since m+t=9

3+t=9

t=9-3=6

The Number of Pieces of Cake Left in Total=x-(t+m)

Since Troy had \frac{1}{4} of the total cake

\frac{1}{4} of x=6

\frac{1}{4} X x=6

x=6X4=24

(a)There are 24 cakes in total

(b)The Number of Pieces of Cake Left in Total=x-(t+m)=24-9=15 cakes

5 0
2 years ago
Let f(x) =7x-13. Find f -1(x)
muminat
If you’re trying to find f(-1) it would be -20
5 0
3 years ago
Read 2 more answers
Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6
yan [13]
Each curve completes one loop over the interval 0\le t\le2\pi. Find the intersections of the curves within this interval.

6-6\sin\theta=6\implies 1-\sin\theta=1\implies \sin\theta=0\implies \theta=0,\theta=\pi

The region of interest has an area given by the double integral

\displaystyle\int_\pi^{2\pi}\int_6^{6-6\sin\theta}r\,\mathrm dr\,\mathrm d\theta

equivalent to the single integral

\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta

which evaluates to 9\pi+72.

8 0
3 years ago
teacher has 27 students in her class she asked the students to form as many groups of 4 as possible how many students are not be
stepan [7]
If there are 27 students in the class and they have to form as many groups of 4 as possible, you can calculate this using the following step: 

27 / 4 = 6.75 = 6 3/4

Result: 27 students can form 6 groups of 4 students and 3 students have to form their own group.
4 0
2 years ago
John has a boat that will travel at the rate of 15 kph in still water. He can go upstream for 35 km in the same time it takes to
Otrada [13]

Answer:

The boat traveling at 24 kph when John goes downstream.

Step-by-step explanation:

We are given the following in the question:

John has a boat that will travel at the rate of 15 kph in still water.

Let x be the speed of the current.

Speed of boat in upstream

(15-x)\text{ kph}

Speed of water in downstream

(15+x)\text{ kph}

Relation:

\text{Speed} = \dfrac{\text{Distance}}{\text{Time}}

We have to find the speed of boat in downstream.

Time to travel upstream for 35 km = Time to travel  140 km downstream

\displaystyle\frac{35}{15-x}=\frac{140}{15+x}\\\\35(15+x) = 140(15-x)\\525 + 35x = 2100 - 140x\\175x = 1575\\x = 9

Thus, speed of current is 9 kph.

Speed of boat in downstream = 15 + 9 = 24 kph.

Thus, the boat traveling at 24 kph when John goes downstream.

4 0
3 years ago
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