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3 years ago

2.300 in word form and the value of 3

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

8 0

Two and Three Tenths is the word form of 2.300.
The 3 holds the value of Three Tenths.

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Mindy and Troy combined ate 9 99 pieces of the wedding cake. Mindy ate 3 33 pieces of cake and Troy had 1 4 4 1 start fraction

saul85 [17]

Answer:

(a)There are 24 cakes in total

(b)There are 15 pieces of cakes left

Step-by-step explanation:

Let the total cakes=x

Let number of cakes eaten by Mindy=m

Let number of cakes eaten by Troy=t

Now:

m=3

Since m+t=9

3+t=9

t=9-3=6

The Number of Pieces of Cake Left in Total=x-(t+m)

Since Troy had $\frac{1}{4}$ of the total cake

$\frac{1}{4} of x=6$

$\frac{1}{4} X x=6$

x=6X4=24

(a)There are 24 cakes in total

(b)The Number of Pieces of Cake Left in Total=x-(t+m)=24-9=15 cakes

5 0

2 years ago

Let f(x) =7x-13. Find f -1(x)

muminat

If you’re trying to find f(-1) it would be -20

5 0

3 years ago

Read 2 more answers

Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6

yan [13]

Each curve completes one loop over the interval $0\le t\le2\pi$ . Find the intersections of the curves within this interval.

$6-6\sin\theta=6\implies 1-\sin\theta=1\implies \sin\theta=0\implies \theta=0,\theta=\pi$

The region of interest has an area given by the double integral

$\displaystyle\int_\pi^{2\pi}\int_6^{6-6\sin\theta}r\,\mathrm dr\,\mathrm d\theta$

equivalent to the single integral

$\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta$

which evaluates to $9\pi+72$ .

8 0

3 years ago

teacher has 27 students in her class she asked the students to form as many groups of 4 as possible how many students are not be

stepan [7]

If there are 27 students in the class and they have to form as many groups of 4 as possible, you can calculate this using the following step:

27 / 4 = 6.75 = 6 3/4

Result: 27 students can form 6 groups of 4 students and 3 students have to form their own group.

4 0

2 years ago

John has a boat that will travel at the rate of 15 kph in still water. He can go upstream for 35 km in the same time it takes to

Otrada [13]

Answer:

The boat traveling at 24 kph when John goes downstream.

Step-by-step explanation:

We are given the following in the question:

John has a boat that will travel at the rate of 15 kph in still water.

Let x be the speed of the current.

Speed of boat in upstream

$(15-x)\text{ kph}$