The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
Answer: 2%
Step-by-step explanation:
Let A be the event of having defective steering and B be the vent of having defective brake linings.
Given: P(A) = 0.03 P(B) = 0.05
P(neither A nor B ) = 0.94
Using formula: P(either A nor B) = 1- P(neither A nor B )
= 1-0.94
i.e. P(either A nor B) =0.06
Using formula:P(A and B) = P(A)+P(B)-P(either A or B)
P(A and B) =0.03+0.05-0.06
= 0.02
Hence, the percentage of the trucks have both defects = 2%
X
4
−34x
2
+225=0
2 Factor
x
4
−
34
x
2
+
225
x
4
−34x
2
+225.
(
x
2
−
25
)
(
x
2
−
9
)
=
0
(x
2
−25)(x
2
−9)=0
3 Solve for
x
x.
x
=
±
5
,
±
3
x=±5,±3