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Savatey [412]
3 years ago
6

How many 5-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?

Mathematics
1 answer:
valentinak56 [21]3 years ago
5 0
50 different 5-digit numbers because it would be 5x10 which equals 50.
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Answer:

Step-by-step explanation:

x° + y° = 180°

2y° - 0.5x° = 180°

y° = 108°

x° = 72°

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Need help with 7, 8, and 9 plz :]
Lelechka [254]
7 .is 9 to the power of 8,number 8 is 5,number 9 is 5m^2n
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2 years ago
1. Based on the information in the table, is the cost of the apples proportional to the weight of apples?
lina2011 [118]

Answer:

  1. yes
  2. no

Step-by-step explanation:

When a number of similar calculations are required, a spreadsheet can reduce the tedium.

1. The price is a constant $1.88 per pound, so is proportional to the weight.

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2. The price is not proportional to the number of toppings.

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The cost of the pizza is $8.99 plus $1.50 per topping. The base cost being non-zero ensures that the overall cost is not proportional to the number of toppings.

4 0
2 years ago
Which number line model represents the expression -2 + 4.5 ?
Lana71 [14]

Answer:

the second pic. A

Step-by-step explanation:

4 0
3 years ago
Given a rectangle with length of (2x+9)cm and width of (3x+1)cm.Two squares, each with sides x cm is removed from the rectangle.
il63 [147K]

Answer: The length is 13cm and the width is 7cm

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = W*L

In this case we have:

L = (2*x + 9) cm

W=(3*x + 1) cm

Then the area of the rectangle is:

A = (2*x + 9)*(3*x + 1) cm^2

A = (6*x^2 + 2*x + 27*x + 9) cm^2

A = (6*x^2 + 29*x + 9) cm^2

now we remove two squares with sides of x cm

The area of each one of these squares is (x cm)*(x cm)  = x^2 cm^2

Then the area of the figure will be:

area = (6*x^2 + 29*x + 9) cm^2 - (2*x^2 ) cm^2

area = (4*x^2 + 29*x + 9) cm^2

Now we know that the area of this shape is 83 cm^2, then we need to solve:

83 cm^2 = (4*x^2 + 29*x + 9) cm^2

0 =  (4*x^2 + 29*x + 9) cm^2 - 83 cm^2

0 = (4*x^2 + 29*x - 74) cm^2

Then we need to solve:

0 = 4*x^2 + 29*x - 74

Here we can use Bhaskara's equation, the solutions of this equation are given by:

x = \frac{-29 \pm \sqrt{29^2 - 4*4*(-74)}  }{2*4} = \frac{-29 \pm 45}{8}

Then the two solutions are:

x = (-29 - 45)/8 = -9.25  (for how the length and width are defined, we can not have x as a negative number, then this solution can be discarded).

The other solution is:

x = (-29 + 45)/8 = 2

x = 2

Then the length and width of the rectangle are:

Length = (2*2 + 9)cm = 13 cm

Width = (3*2 + 1)cm = 7cm

4 0
2 years ago
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