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2 years ago

What values of b make it an exponential growth function

Mathematics

2 answers:

Inessa05 [86]2 years ago

6 0

Answer:

b > 1

Step-by-step explanation:

If b is the base, it has to be greater than 1

blondinia [14]2 years ago

6 0

Answer: when b is greater than 1

Step-by-step explanation:

The growth rate is determined when b= 1+r

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Help please!!!!!

Sergio [31]

Answer:

a. image 1

Step-by-step explanation:

Given function:

f(x) = 2*3ˣ

Plot two points and check which graph has those:

f(0) = 2*3⁰ = 2

and

f(1) = 2*3¹ = 6

Points (0, 2) and (1, 6) are correct on the image 1 with blue graph

7 0

2 years ago

What is the third term of the sequence defined by the recursive rule f(1)=3 f(n)=f(n-1)+4

snow_tiger [21]

What is the third term of the sequence defined by the recursive rule f(1)=3 f(n)=f(n-1)+4

Need f(2):

f(2)=f(2-1)+4
f(2)=f(1)+4
f(2)=(3)+4=7

FIND f(3):
f(3)=f(3-1)+4
f(3)=f(2)+4
f(3)=(7)+4
f(3)=11

5 0

2 years ago

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

3 years ago

Math question down below

Andrei [34K]

Eq. of given line is x = -2 》x + 2 = 0

6 0

2 years ago

Harry estimate that his dinner will have 48g of fat her total allowance is 70g what percentage of her total daily allowance of f

boyakko [2]

Х = 48 * 100 : 70 - the proportion
х = 67 g is her total daily allowance of fat

7 0

2 years ago

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