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Masja [62]
3 years ago
12

Find the value of the x in the equation 9x+15=8x

Mathematics
1 answer:
zheka24 [161]3 years ago
3 0

9x+15=8x

subtract 15 and 8x from both sides to get

x=-15

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Solve the equation 7x - 12 = 23<br> What is the answer
siniylev [52]
The answer is 5 I have shown my work in the picture

8 0
2 years ago
Read 2 more answers
What is the total area, in square inches, of the shaded sections of the trapezoid
jeyben [28]
First:

Break the shape into parts, this shape can be broken into 3 parts.

Next :
Put the equation for each shape

Shape 1 ( left shape)
L x h
5.4 in x 4.8 in = 25.95 in

Shape 2 (middle shape)
L x H
5in x 4.8in = 24in

Shape 3 ( right shape)
L x H
7.9 in x 4.8 in = 37.92 in

Last:
Add them all up

25.95 in
+ 24in
37.92in
——————
87.87in

Answer
87.87 in 2

I hope this helped and that I was right, have a nice day.


6 0
3 years ago
Help Asap will give brainliest if you start answering by 21 minutes
Elza [17]

<u>Answer:</u>

f(x) = (2x + 1)(2x − 1)

Explanation:

As we can see from the above function f(x) = 4x^{2} − 1, we need to find x-intercept, i.e., the value of x where this function's value is zero.

So let us Equate the function with zero

4x^{2} - 1 = 0 => 4x^{2} = 1 => x^{2} = 1/4 => x = \sqrt{1/4}

Hence we get 2 values of x, i.e., +1/2, and -1/2.

So now we need to check out the functions which are zero at this values of x, so let us substitute values of x in each and every option and see the values of functions.

Option A - f(x) = (4x + 1)(4x − 1) = 3, -3

Option B - f(x) = (2x + 1)(2x − 1)  = 0

Option C - f(x) = 4(x2 + 1)  = 5

Option D - f(x) = 2(x2 − 1) = -3/2

Hence answer is Option B

8 0
3 years ago
Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200
-Dominant- [34]

Answer:

 1348 light years.    

Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.  

(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)

Upon substituting our given values in above formula we will get,

x^2=1200^2+1700^2-2*1200*1700*cos (52^o)  

x^2=1440000+2890000-4080000*0.615661475

x^2=4330000-2511898.81933008

x^2=1818101.18066992

Let us take square root of both sides of our equation.

x=\sqrt{1818101.18066992}

x=1348.3698234\approx 1348

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

6 0
3 years ago
TAKE A SNIPER TAKE A SHOT TAKE THESE POINTS.
gulaghasi [49]

Answer:

1.5

Step-by-step explanation:

(6,-4)*1.5=(9,-6)

(2,-8)*1.5=(3,-12)

7 0
3 years ago
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