The three numbers are 12, 18 and 24
Arithmetic progression
Let the 3 number in arithmetic progression be:
a-d, d, a+d ...
If their sum is 3, then;
a-d+d+a+d = 3
2a + d = 3 ........... 1
If the sum of their squares is 11, then;
(a-d)² + d² + (a+d)² = 11
a²-2ad+d²+d²+a²+2ad+d² 11
2a²+3d² = 11 ....... 2
Solving the equations simultaneously, d = 6 and a = 12
First-term = 12
second term = 18
Thirs term = 24
Hence the three numbers are 12, 18 and 24
Hope this helps you!!!!!! :D
Alright in this one, you are going to need to factor.
The width is x
The length is 2x-4
To find the area of a rectangle is L*W
so (2x-4)(x) when distributed is 2x^2 -4x
Then put that in the equation and you have:
2x^2 -4x = 96
2x^2 -4x -96 = 0
2x^2+12x-16x-96=0
3x(x+4)-4(x+4)=0
(3x-4)=0
(x+4)=0
x=-4
<u>x=3/4</u>
Since length isn't negative
we will use <u>3/4 as x.
</u>
Width= 0.75 ft
Length= 1.5
Answer:
7
Step-by-step explanation:
Since 14 divided by 2 is 7, you can get 7 bulbs of elephant garlic.
Hope this helps.
