Ask question

Ask question

All categories

3 years ago

9

What is 2.8 as a fraction in simplest form

2 answers:

irina1246 [14]3 years ago

8 0

2.8 = 2 + 0.8

*let's analyze the decimal 0.8 as a fraction

0.8 = 8/10

*but if we divide the numerator and denominator by the same common factor of 2, we find that the fraction can be reduced to:

(8/2)/(10/2) = (4)/(5) = 4/5

*now evaluating the whole value of 2 (from the 2.8), we know there are a total of (5) - fifths in order to make a whole, so for 2 whole, we require:

2*(5/5) = (2*5)/5 = 10/5

*Now we add the fractions together:

2 = 10/5
0.8 = 4/5

10/5 + 4/5

*add numerators only, the denominator stays as a 5

(10 + 4)/5 = 14/5

*there are no common factors between 14 & 5 (other than 1, but that won't help reduce the fraction any), so the fraction is in it's simplest form:

answer is: 14/5

zhannawk [14.2K]3 years ago

3 0

2.8

= 2.0 + 0.8

= 2 + 4/5

= 10/5 + 4/5

= 14/5

You might be interested in

Using the point-slope formula, what is the equation of the line that passes through the points (1,5) and (0, 0)?

DerKrebs [107]

Answer:

y =5x

Step-by-step explanation:

$y_{1}-y_{2} = m(x_{1} - x_{2} )$

(5 - 0) = m(1 - 0)

5 = m(1)

5 = m

$y_{1}-y_{2} = m(x_{1} - x_{2} )$

y - 5 = 5(x - 1)

y - 5 = 5x - 5

y = 5x -5 + 5

y = 5x

7 0

3 years ago

Yesterday, it took 40 minutes to drive to school. Today, it took 32 minutes to drive to school. What is your percent of change?

Citrus2011 [14]

Step-by-step explanation:

decrease by 20%

xxxxxxxx

4 0

3 years ago

Read 2 more answers

Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t

katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on $y=x$ line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

$(x,y)\rightarrow (y,x)$

Points on line EF

$(0,6) , (-5,-2)$

On reflection of this line on $y=x$ the new points we get for line JK are

$(6,0),(-2,-5)$

Points on line GH

$(-4,9),(-9,1)$

On reflection on y=x line the new points we get for line LM are

$(9,-4),(1,-9)$

Slope of line JK

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}$

Slope of line LM

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}$

For two line to be parallel, their slopes will be same.

$m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}$

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

5 0

3 years ago

A cube has depth of 10 cm. What is the volume of the cube?

shusha [124]

The answer is 10x10x10=1,000
ten times ten times ten is one thousand

8 0

3 years ago

The circumference of a circle is 15π ft. What is the area, in square feet? Express your answer in terms of π.

DerKrebs [107]

Answer:

Area of the circle is 56.25π square feet.

Step-by-step explanation:

<u>Given that</u>:

The circumference of a circle is 15π ft.

<u>To Find</u>:

What is the area, in square feet?

<u>We know that</u>:

Circumference of a circle = 2πR
Area of a circle = πR²

Where,

Radius is denoted as R.

<u>Finding the radius of the circle</u>:

Circumference of a circle = 15π

⟶ 2πR = 15π

⟶ 2πR = 2π × 7.5

Cancelling 2π.

⟶ R = 7.5

∴ Radius of the circle = 7.5 ft.

<u>Finding the area of the circle</u>:

⟶ Area = πR²

⟶ Area = π(7.5)²

⟶ Area = π × 7.5 × 7.5

⟶ Area = π × 56.25

⟶ Area = 56.25π

∴ Area of the circle = 56.25π ft.²

7 0

3 years ago