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2 years ago

4. If two straight lines intersect and one angle is 30°, what are the other three angles?

2 answers:

6 0

The answer is C.

this is because one other angle will be equal to the first angle of 30°

The other two are equal to $\frac{360- (30 +30)}{2} =150$ °

Sedbober [7]2 years ago

3 0

The answer is B. It's B because a straight line has a degree of 180, if you have 2, then of course it becomes 360. In B, you have 90, 90, and 150. If one of the angles is 30, you add that onto 150 to get 180 and add 90 and 90 together to get 180. Naturally, add those two answers together to get 360.

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Find the value of x please hurry

Andrei [34K]

Answer:

x+133= 130

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Step-by-step explanation:

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2 years ago

The Tennessee Titans scored 22 points in week 5 and 35 points in week 6. Find the percent of increase.

Shalnov [3]

Answer:

59.09%

Step-by-step explanation:

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13/2= .59090909=59.09%

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2 years ago

The midpoint of (3 x, -2) and (-4, 5y) is (1,4). find x, -y

Mariana [72]

Answer:

(x,-y): (2,-2)

Step-by-step explanation:

M=(x+x)/2,(y+y)/2

Given (1,4)=

$\frac{3x - 4}{2}$

This implies:

$1 = \frac{3x - 4}{2}$

$3x - 4 = 2 \\ 3x = 2 + 4 \\ \frac{3x }{3} = \frac{6}{3} \\ x = 2$

In a similar way,

$4 = \frac{ - 2 + 5y}{2} \\ - 2 + 5y = 8 \\ 5y = 10 \\ y = 2$

The question demanded (x,-y)

Hence(2,-2) is the answer

7 0

2 years ago

Marsha wants to determine the vertex of the quadratic function f(x) = x2 – x + 2. What is the function’s vertex?

BaLLatris [955]

Answer:

$Vertex = (\frac{1}{2},\frac{7}{4})$

Step-by-step explanation:

Given

$f(x) = x^2 - x +2$

Required

The vertex

We have:

$f(x) = x^2 - x +2$

First, we express the equation as:

$f(x) = a(x - h)^2 +k$

Where

$Vertex = (h,k)$

So, we have:

$f(x) = x^2 - x +2$

--------------------------------------------

Take the coefficient of x: -1

Divide by 2: (-1/2)

Square: (-1/2)^2

Add and subtract this to the equation

--------------------------------------------

$f(x) = x^2 - x +2$

$f(x) = x^2 - x + (-\frac{1}{2})^2+2 -(-\frac{1}{2})^2$

$f(x) = x^2 - x + \frac{1}{4}+2 -\frac{1}{4}$

Expand

$f(x) = x^2 - \frac{1}{2}x- \frac{1}{2}x + \frac{1}{4}+2 -\frac{1}{4}$

Factorize

$f(x) = x(x - \frac{1}{2})- \frac{1}{2}(x - \frac{1}{2})+2 -\frac{1}{4}$

Factor out x - 1/2

$f(x) = (x - \frac{1}{2})(x - \frac{1}{2})+2 -\frac{1}{4}$

$f(x) = (x - \frac{1}{2})^2+2 -\frac{1}{4}$

$f(x) = (x - \frac{1}{2})^2+ \frac{8 -1 }{4}$

$f(x) = (x - \frac{1}{2})^2+ \frac{7}{4}$

Compare to: $f(x) = a(x - h)^2 +k$

$h = \frac{1}{2}$

$k = \frac{7}{4}$

Hence:

$Vertex = (\frac{1}{2},\frac{7}{4})$

8 0

3 years ago

Read 2 more answers

Determine if (-2,6) and (4,12) are solutions to the system of equations:

kykrilka [37]

Answer:

Both $(-2,6)$ and $(4,12)$ are solutions to the system.

Step-by-step explanation:

In order to determine whether the two given points represent solutions to our system of equations, we must "plug" thos points into both equations and check that the equality remains valid.

Step 1: Plug $(-2,6)$ into $y=x+8$