H>12 and w>12 however p≤60
p=2(h+w) but give what we have above for h and w
p>48 so p must satisfy the solution set:
48<p≤60 and since p=2(h+w)
48<2(h+w)≤60
24<h+w≤30
So there are infinitely many solutions if h and w are not restricted to integer values...
(h,w) vary from (12,18) to (18,12) Note that neither endpoints exist, 12 because it is explicitly excluded and 18 because that would make the other dimension 12 which is excluded...
Now if you are just talking integer values, there are only:
(13,17),(14,16),(15,15),(16,14),(17,13)
Answer:
6 minutes
Step-by-step explanation:
Mr Crenshaw checks at a rate of 1/10 and Mr. Aguirre checks at a rate of 1/15.
If they work together, they will be checking at a combined rate of:
1/10 + 1/15 = [3(1) + 2(1)]/30
= 5/30 = 1/6
Their combined rate is 1/6 which means they check one set in 6 minutes
460/100 = 4.60 x 35 = 161 + 460 = $621
Answer:
1 in 720 chance of getting the word TIGERS.
Step-by-step explanation: