Answer:
for the first line let (-4,-3) be (x1,y1) and (8,0) be x2,y2.
now,
slope (m1) = (y2-y1)/ (x2-x1)
or, m1= 0-(-3)/ 8-(-4)
or, m1=3/12=1/4
again, for line two consider (0,2) as x1,y1 and (-1,6) be (x2,y2)
apply the same formula and find the slope(m2)
m2=6-2/-1-0
or, m2=4/-1
for b) m1 multiply m2
or 1/4 x 4/-1
=-1 so it is perpendicular
Step-by-step explanation:
for a we simply apply the formula of slope considering the given points as x1,y1 and x2,y2 respectively.
while for the b number if m1 x m2 =-1 the line is considered to be perpendicular.
similarly, if m1=m2 then it is considered to be parallel.
here m1 is slope of the first line, m2 is slope of second line and m3 is the slope of the third line
