1) -3/2 × 4x = -6x
2) -3/2 × 3 = -9/2
Answer: -6x−9/2
Answer:
Step-by-step explanation:
y - 3 = -6(x - 4)
y - 3 = -6x + 24
y = -6x + 27
Answer:
HL
Step-by-step explanation:
The hypotenuse and the "leg" are congruent...along with the 90 degree angle.
"The HL Postulate states that if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent." - Calcworkshop
First, an introduction: If the equation of the circle were x^2 + y^2 = 144, then the center would be at (0,0) and the radius would be 12. Note that the distance from the center to P(10,10) is 10sqrt(2), or 14.14. Thus, in this example, P would be OUTSIDE the circle (since 14.14 is greater than the radius 12).
Now let's focus on <span>(x-1)^2 + (y-2)^2 =144. Let x = 12 as an example; find the corresponding y: 9^2 + (y-2)^2 = 144, or (y-2)^2 = 63, and so y-2 is approx. -8 or +8. Then y (for x = 12) is either approx. -10 or 6: (12,-10) or (12,6). Are these inside the circle or outside?
A better way to address this would be as follows:
Find the distance from the center (1, 2) to the point P(10,10). If this distance is less than 12, the point P is inside C; if greater than 12, P is outside C.
This distance is sqrt( (10-2)^2 + (10-1)^2 ), or sqrt (64+81) = sqrt(145).
This is LARGER than sqrt(144). Thus, P is OUTSIDE the circle C.</span>
