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mariarad [96]
3 years ago
7

Simon wants to use both area formulas shown to find the area of the trapezoid. How can he divide the trapezoid to do that?

Mathematics
2 answers:
Ierofanga [76]3 years ago
7 0

Answer:

Step-by-step explanation:

the third one the one that has 2 triangle and 1 square

diamong [38]3 years ago
3 0
I think it might be the last one I am sorry if I am rong.
You might be interested in
Help, and if you can give me a step by step explanation
Llana [10]

Answer:

the first option

Step-by-step explanation:

variability !

what does that word tell us ?

it means that there are more individuals differences.

you could also use "accuracy" as the opposite - we are aiming for the mean value ...

imagine some bow and arrow tournament.

who wins ?

the person with the highest accuracy across all the attempts (and that means the lowest variability in the results across all attempts relatively to the target center representing the predefined mean value).

now look at the graphic for neighborhood A.

and then for neighborhood B.

which one has the data points more clustered around the center (where the mean value is going to be) ? this one has lower variability than the one where the data points are having more than one cluster or are even all over the place.

remember, for the variability you have to add all the differences to the mean value. the smaller the differences to the mean value, the smaller the variability.

in neighborhood B almost all data points have a larger difference to the mean value.

so, the variability will be higher here.

5 0
2 years ago
Plz help :( im trying to understand this but Idk how it works?
djyliett [7]

Answer:

LEFT

k + 3 = 20,

k = 17

RIGHT

3x + 5 = 32,

k = 9

Step-by-step explanation:

For the left side, you have k + 3 on one side equaling 20, so the equation is

k + 3 = 20

To solve is as follows

k + 3 = 20

  - 3    - 3

     k = 17

For the right side,

You have 3 x's and 5 1's right? Adding them together will equal 32 (Other side

So your equation is 3x + 5 = 32

To solve is as follows

3x + 5 = 32

    - 5     -5

      3x = 27

Dividing both sides by 9 we get x = 9

Reasoning; you want to cancel out everything with x so that you got x alone on one side.

Hope this helps, if not comment on this telling me which step I did that you dont understand and I'll explain it.

4 0
3 years ago
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 11z on the curve of intersection of the plane x − y + z =
Taya2010 [7]

Answer:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

<em>Maximum value of f=2.41</em>

Step-by-step explanation:

<u>Lagrange Multipliers</u>

It's a method to optimize (maximize or minimize) functions of more than one variable subject to equality restrictions.

Given a function of three variables f(x,y,z) and a restriction in the form of an equality g(x,y,z)=0, then we are interested in finding the values of x,y,z where both gradients are parallel, i.e.

\bigtriangledown  f=\lambda \bigtriangledown  g

for some scalar \lambda called the Lagrange multiplier.

For more than one restriction, say g(x,y,z)=0 and h(x,y,z)=0, the Lagrange condition is

\bigtriangledown  f=\lambda \bigtriangledown  g+\mu \bigtriangledown  h

The gradient of f is

\bigtriangledown  f=

Considering each variable as independent we have three equations right from the Lagrange condition, plus one for each restriction, to form a 5x5 system of equations in x,y,z,\lambda,\mu.

We have

f(x, y, z) = x + 2y + 11z\\g(x, y, z) = x - y + z -1=0\\h(x, y, z) = x^2 + y^2 -1= 0

Let's compute the partial derivatives

f_x=1\ ,f_y=2\ ,f_z=11\ \\g_x=1\ ,g_y=-1\ ,g_z=1\\h_x=2x\ ,h_y=2y\ ,h_z=0

The Lagrange condition leads to

1=\lambda (1)+\mu (2x)\\2=\lambda (-1)+\mu (2y)\\11=\lambda (1)+\mu (0)

Operating and simplifying

1=\lambda+2x\mu\\2=-\lambda +2y\mu \\\lambda=11

Replacing the value of \lambda in the two first equations, we get

1=11+2x\mu\\2=-11 +2y\mu

From the first equation

\displaystyle 2\mu=\frac{-10}{x}

Replacing into the second

\displaystyle 13=y\frac{-10}{x}

Or, equivalently

13x=-10y

Squaring

169x^2=100y^2

To solve, we use the restriction h

x^2 + y^2 = 1

Multiplying by 100

100x^2 + 100y^2 = 100

Replacing the above condition

100x^2 + 169x^2 = 100

Solving for x

\displaystyle x=\pm \frac{10}{\sqrt{269}}

We compute the values of y by solving

13x=-10y

\displaystyle y=-\frac{13x}{10}

For

\displaystyle x= \frac{10}{\sqrt{269}}

\displaystyle y= -\frac{13}{\sqrt{269}}

And for

\displaystyle x= -\frac{10}{\sqrt{269}}

\displaystyle y= \frac{13}{\sqrt{269}}

Finally, we get z using the other restriction

x - y + z = 1

Or:

z = 1-x+y

The first solution yields to

\displaystyle z = 1-\frac{10}{\sqrt{269}}-\frac{13}{\sqrt{269}}

\displaystyle z = \frac{-23\sqrt{269}+269}{269}

And the second solution gives us

\displaystyle z = 1+\frac{10}{\sqrt{269}}+\frac{13}{\sqrt{269}}

\displaystyle z = \frac{23\sqrt{269}+269}{269}

Complete first solution:

\displaystyle x= \frac{10}{\sqrt{269}}\\\\\displaystyle y= -\frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{-23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=-0.4

Complete second solution:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=2.4

The second solution maximizes f to 2.4

5 0
3 years ago
Bobby catches 8 passes in 3 football games. At this rate, how many asses does he catch in 15 games?
marshall27 [118]

Answer:

40

Step-by-step explanation:

8:3 So divide 15 by 3.  you get 5. Multiply 5 by 8 and you get 40

4 0
3 years ago
Explain why the diagram shows that<br> 6(3 + 4) = 6.3 +6.4.
spin [16.1K]
Who that even possible 6(3+4) is 6*3 + 6*4= 42
3 0
3 years ago
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