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3 years ago

Which equation can be used to find the measure of angle BAC?

Mathematics

2 answers:

asambeis [7]3 years ago

8 0

Answer:

Step-by-step explanation:

let angle $B$ . be $y$ then,

using angle sum property,

x+y+90=180 (angle c is 90 because its given)

hence you have the equation

Monica [59]3 years ago

6 0

Answer:

Cos() = AC / AB

So in this case: Cos() = 5 / 13

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Della Ahkta has a whole life policy for $50,000. She pays an annual premium rate of $13.47 per

ehidna [41]

Answer:

645.56

Step-by-step explanation:

50000/1000 13.37=673.50

673.50

-27.94

4 0

3 years ago

Ann went to the store after school 5 days this week. Each day, she bought a sandwich and a comic book. She spent a total $50 of

Lubov Fominskaja [6]

In total 5 days, she has paid: 5 x $2 = $10 for the sandwiches

In total 5 days, she has paid: $50 - $10 = $40 for the comics

So, she paid: $40 / 5 = $8 for each comic

If helpful, brainliest please !

5 0

2 years ago

n your notebook, set up the following subtraction in a vertical format and select the correct answer. Reduce 7y + 2y 2 - 7 by 3

exis [7]

Answer:

$\frac{2y^2+7y-7}{3-4y}$

Step-by-step explanation:

We are given

$\frac{7y+2y^2-7}{3-4y}$

we can rewrite it as

$\frac{2y^2+7y-7}{3-4y}$

we know that

2y^2+7y-7 can not be factored

so, we can not reduce this expression

because this is the only way to reduce it

so, we get reduced form as

$\frac{2y^2+7y-7}{3-4y}$

6 0

2 years ago

Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with

worty [1.4K]

Answer:

$z$

Step-by-step explanation:

Assuming this complete question:

"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean $\mu =26$ kilograms and standard deviation $\sigma=4.2$ kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.

$X$ "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(26,4.2)$

Where $\mu=26$ and $\sigma=4.2$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.

We can convert the corresponding z score for x=42.6 like this:

$z=\frac{42.6-26}{4.2}=3.95$

So then the corresponding z scale would be:

$z$

7 0

2 years ago

Charles wants to find out if the students in foreign language classes spend more time in class speaking in English or in the for

Hunter-Best [27]

The samples he chose may not be a representative sample because the number of students per foreign language class may not be the same. One class may have a very large number of students while another may have only a few. Taking equal number of students per class is not a representative sample.

6 0

3 years ago

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