I'm not sure what this means. If you have choices you should list them.
(1/2)*(1/4 + 1/6) is an example of what should be given. There are two ways to solve this.
1. Use the distributive property.
1/2*1/4 + 1/2* 1/6
1/8 + 1/12 Which can be added using the LCD of 24
3/24 + 2/24 = 5/24
Method 2
Add what is inside the brackets first.
1/2 ( 1/4 + 1/6)
1/2(3/12 + 2/12 = 5/12
Now multiply by 1/2
1/2(5/12) = 5*1/(12 * 2) = 5 / 24 Same answer.
Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
Answer:
6.8% decrease
Step-by-step explanation:
a drop of 8% means that only 92% of 125 boys remained on honor roll from last year; .92 x 125 = 115
a drop of 5% means that only 95% of 80 girls remained on honor roll from last year; .95 x 80 = 76
total number of students on honor roll last year = 125 + 80 = 205
total number of students on honor roll this year = 115 + 76 = 191
percent of change = (191 - 205) ÷ 205 = -14/205 = -.068
-.068, which represents a 6.8% decrease
12a + 6 + 3a = 15a + 2
15a = 15a - 4
0 = - 4
