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worty [1.4K]
3 years ago
9

A six sides dice rolls twice. What is the probability that the first roll is a even number and the second roll is a number great

er than 4?
Mathematics
1 answer:
zalisa [80]3 years ago
7 0
Answer - 1/6

EXPLANATION

For a six sides dice:
Possible numbers are: 1, 2, 3, 4, 5, and 6
Total of 6 possible numbers

Possible even number outcomes are: 2, 4, and 6
Total of 3 outcomes out of 6 possibilities
Probability that the roll is a even number, p(A) = 3/6
p(A) = 3/6 = 1/2


<span>Possible outcomes greater than 4 are: 5 and 6
Total of 2 outcomes out of 6 possibilities
</span>Probability that the roll is a number greater than 4, p(B) = 2/6
p(B) = 2/6 = 1/3

The probability that the first roll is a even number and the second roll is a number greater than 4 = p(A and B)
p(A and B) = p(A) x p(B)


p(A) = 1/2
p(B) = 1/3
p(A and B) = p(A) x p(B)
= 1/2 * 1/3
= 1/6
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