<span><span>Given the equation of a circle"<span>x^2 + y^2 - 4x +6y -36 = 0</span>We will use completing the square method to rewrite the equation into the form:(x-a)^2 + (y-b)^2 = r^2 where (a,b) is the center and r is the radius.Let us rewrite the terms.==> x^2 - 4x + y^2 + 6y = 36Now we will complete the square for both x^2 ands y^2.We will add [( coefficient of x)/2]^2 and [(coefficients of y)/2]^2 to both sides.Then we will add :(4/2)^2 = 2^2 = 4(6/2)^2 = 3^2 = 9Then we will add 4 and 9 to both sides.==> x^2 - 4x +4 + y^2 + 6y + 9 = 36 + 4 + 9==> (x-2)^2 + (y+3)^2 = 49==> (x-2)^2 + (y+3)^2 = 7^2Now we will compare the equation withe the standard form of a circle.Then we conclude that:<span>The center of the circle is: ( 2, -3) and the radius is 7.</span></span></span>
Answer:
8 grams
Step-by-step explanation:
The balance is in equilibrium, so the weights of the two sides are equal.
Let the weight of a square be s.
Left side: 2s + 4
Right side: s + 3(4) = s + 12
The weights are equal, so we set the two expressions equal.
2s + 4 = s + 12
s = 8
Answer: The weight of a square is 8 grams.
PLS MARK ME AS BRAINIEST
Answer: 60 cents
Step-by-step explanation: 1 Dime= 10 cents; 10x6= 60.
Answer:
y = 3·2^x
Step-by-step explanation:
At x=0, f(0) = a = 3
At x=1, f(1) = a·b = 3b = 6 ⇒ b = 6/3 = 2
So, the function is ...
f(x) = 3·2^x
The base is 2, the exponent is 5. You're welcome. ;)
