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hjlf
3 years ago
9

Ms. Rodriguez broyght 10 oranges for afternoon snak that she needs to share evenly with the 15 players on her daughters soccer t

eam. should she cut the oranges in halves, thirds, or quarters? justify your answer​
Mathematics
1 answer:
daser333 [38]3 years ago
5 0

Answer:

she should cut them into thirds

Step-by-step explanation:

there are 10 oranges while there are 15 players.

a) if she cuts them into halves, she will have 20 slices with 5 left over, who will get an extra slice while who doesn't? it can't work  

b) if she cuts them into thirds, she will have 30 slices with 15 left over, that is enough to give each player two slices with none left over, it works!!

c) if she cuts them into quarters, she would have 40 slices with 25 left over. this means some players would get three slices, while others would only get two. it doesn't work.

this is why B is the right answer

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Taya2010 [7]
Area = (1/2) * 4 * 5 = 10 cm²
8 0
3 years ago
I need the answer fast I am in schoool pls
Stolb23 [73]

Answer:

288

Step-by-step explanation:

To solve, we need to find the area of the four triangle sides and add that to the square base's area.

Area of triangle sides: base * height * 0.5

Area of square base: base * height

Substitute the values

8 * 14 * 0.5 = 56

There are four of these sides, so the area of all the triangles is 224.

The square base is 8 * 8, or 64

Add these two values together.

64 + 224 = 288

Thus, the answer is 288

8 0
2 years ago
Circle P and circle Q are similar. What is the scale factor which converts P to Q?
andriy [413]

Answer: C

Step-by-step explanation:

To find the scale factor between circle P and circle Q, divide the diameter of circle Q by the diameter of circle P, 4.5 ft÷1.5 ft = 3. The scale factor between circle P and circle Q is 3.

3 0
3 years ago
Read 2 more answers
Could someone help with this?
Citrus2011 [14]

the answer is 4 and 7                

3 0
3 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
3 years ago
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