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hram777 [196]
3 years ago
12

81^5=3^x What does “x” equal?

Mathematics
1 answer:
Lynna [10]3 years ago
7 0

Answer:

x =2 0

Step-by-step explanation:

{81}^{5}  =  {3}^{x}

We know that 3^4 = 81. So :

=  >  { ({3}^{4}) }^{5}  =  {3}^{x}

=  >  {3}^{4 \times 5}  =  {3}^{x}

=  >  {3}^{20}  =  {3}^{x}

Here both the Right hand side & Left hand side has same base i.e. have 3 as base in both the sides.

So , eliminating the base gives :-

x = 20

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X - 35 > 15 pleases solve
IrinaVladis [17]
Answer:

x-35>15

x>15+35

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3 years ago
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50 men working 10 hours daily can complete a job in
Sliva [168]

<h2>Given :-</h2>

  • 50 men do 10 hours work daily complete work in 20 days

  • 80 men do job in 50% time

<h2>To Find :-</h2>

  • Days required

<h2>Solution :-</h2>

  • 1 man may do job in (50 × 20) days =
  • 1 man may do job in 1000 days

Now,

  • 80 man = 1000/80 = 12.5

Now,

  • When hours reduced 50% then we will multiply days by 2
  • Total days = 12.5 × 2 = 25 days.

<h2>Hence</h2>

  • Option C is correct

\begin{gathered} \\ \end{gathered}

8 0
2 years ago
While vista his sister in Chicago, Marcus found a t-shirt that cost $ 12.00. If Marcus had to pay 6.25 % in sales taxes , how mu
ddd [48]
0.75 was the tax and 12.75 in total, correct me if I am wrong..
8 0
2 years ago
11+x=-7 <br><br>im using the wall thing with the line though the =. ​
mezya [45]

Answer:

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Step-by-step explanation:

7 0
3 years ago
A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly
shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = \frac{1}{4}

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}

P(First\ White) = \dfrac{3}{10}

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = \frac{1}{4}

4 0
3 years ago
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