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3 years ago

81^5=3^x What does “x” equal?

Mathematics

1 answer:

Lynna [10]3 years ago

7 0

Answer:

$x =2 0$

Step-by-step explanation:

${81}^{5} = {3}^{x}$

We know that 3^4 = 81. So :

$= > { ({3}^{4}) }^{5} = {3}^{x}$

$= > {3}^{4 \times 5} = {3}^{x}$

$= > {3}^{20} = {3}^{x}$

Here both the Right hand side & Left hand side has same base i.e. have 3 as base in both the sides.

So , eliminating the base gives :-

$x = 20$

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X - 35 > 15 pleases solve

IrinaVladis [17]

Answer:

x-35>15

x>15+35

x>50

3 0

3 years ago

Read 2 more answers

50 men working 10 hours daily can complete a job in

Sliva [168]

<h2>Given :-</h2>

50 men do 10 hours work daily complete work in 20 days

80 men do job in 50% time

Days required

<h2>Solution :-</h2>

1 man may do job in (50 × 20) days =
1 man may do job in 1000 days

Now,

80 man = 1000/80 = 12.5

Now,

When hours reduced 50% then we will multiply days by 2
Total days = 12.5 × 2 = 25 days.

<h2>Hence</h2>

Option C is correct

$\begin{gathered} \\ \end{gathered}$

8 0

2 years ago

While vista his sister in Chicago, Marcus found a t-shirt that cost $ 12.00. If Marcus had to pay 6.25 % in sales taxes , how mu

ddd [48]

0.75 was the tax and 12.75 in total, correct me if I am wrong..

8 0

2 years ago

11+x=-7 <br><br>im using the wall thing with the line though the =.

mezya [45]

Answer:

x= -7-11

x=-18

Step-by-step explanation:

7 0

3 years ago

A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly

shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}$

$P(First\ White) = \dfrac{3}{10}$

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

$P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }$

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

4 0

3 years ago