Diagonal of the left triangle = ((8)^2+(7)^2)^0.5= (113)^0.5
x =( 12^2 -(113)^0.5)^2))^0.5=( 144- 113)^0.5= (31)^0.5= 5.57
For ur working, ur mistake lies in the line : x^2+12^2=10.6^2
It shld be 12^2= x^2+10.6^2
<span>2(3 - x) = -16
3 - x = -16/2
3 - x = -8
-x = -8 - 3
-x = - 11
x = 11</span>
Here is the answer to the given problem above. Given that the business owes $8000 on a loan and every month, it pays 1212. So for the first month, the remaining is 6,788. On the second month is 5,576, and on the third month, it is 4,364. In the fourth month, the remaining would be 3,152, and in the fifth month is 1,940. Therefore, on the sixth month, if the business pays 1,212 still, the remaining would be $728 only. Hope this answer helps.
Answer: B
Step-by-step explanation:
Answer:
The domain is all real numbers.
The range is all real numbers.
The graph crosses the y axis once.
The graph increases from negative infinity to positive infinity.
Step-by-step explanation:
The graph crosses the axis when x = 0:
y(0) = (0 - 3)^3 + 1
= -27 + 1
= -26 so it crosses y-axis at (0, -26) only.
Point where it crosses the x axis is when y = 0:
(x - 3)^3 + 1 = 0
(x - 3)^2 = -1
x-3 = cube root of -1 = -1
x = 2. It only crosses the x axis once at (2, 0>
