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AlladinOne [14]
3 years ago
11

Given A(3, 4), B(4, 3) and C(2, 1), what are the coordinates of C', the image of C under a rotation of 90 degrees about the orig

in?
Mathematics
1 answer:
Aleks [24]3 years ago
5 0

<u>Given</u>:

The coordinates of the points A, B and C are (3,4), (4,3) and (2,1)

The points are rotated 90° about the origin.

We need to determine the coordinates of the point C'.

<u>Coordinates of the point C':</u>

The general rule to rotate the point 90° about the origin is given by

(x, y) \Rightarrow(-y, x)

Substituting the coordinates of the point C in the above formula, we get;

(2, 1) \Rightarrow(-1, 2)

Therefore, the coordinates of the point C' is (-1,2)

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Please answer correctly! I will mark Brainliest!
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Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distanc
Anna11 [10]

Answer:

The final velocity v is 21.74 m/s.

Step-by-step explanation:

Given:

\textrm{initial velocity} = u = 9\ m/s\\\textrm{acceleration} = a = 7\ m/s^{2}\\\textrm{distance} = s = 28\ m

To find:

\textrm{final velocity} = v = ?

Solution:

As we know the third equation of motion is represented as

v^{2} = u^{2} + 2\times a\times s\\

Substituting the values u, a and s in the above equation we get

v^{2} = 9^{2} + 2\times 7\times 28\\ =81 + 392\\=473\\

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7 0
3 years ago
An airline finds that 5% of the persons making reservations on a certain flight will not show up for the flight. If the airline
vivado [14]

Answer:

The answer to the question is;

The probability that a seat will be available for every person holding a reservation and planning to fly is 0.63307.

Step-by-step explanation:

Let the sample size =n = 100

The success probability = 5 % = 0.05

Number of tickets sold = 105 tickets

In the case where there the airline has found that 5 % will not show up, then every passenger should have  a seat, we have  

A Binomial distribution is appropriate where there is a chance for a certain number of successful outcomes from a number of independent trails

However n·p and n·q must be ≥ 5 for there to be a normal approximation of a Binomial distribution thus

n·p = 105×0.05 =  5.25 ≥ 5

and n·q = n(1 - p) = 105 (1 - 0.05) = 99.75 ≥ 5

As the requirements are met, we can proceed with the approximation of the Binomial distribution by the normal distribution

 z = \frac{x-np}{\sqrt{np(1-p)}  } = \frac{4.5 - 105*0.05}{\sqrt{105*0.05(1-0.05)} } =  - 0.3358

We therefore have P(x ≥ 5) = P( x > 4.5) = P(z > -0.34) = 1 - P(z < -0.34) = 1 -0.36693 = 0.63307

Another way to solve the question is as follows

p = 0.95 q = 0.05

μ = np = 0.95*105 = 99.75, σ = \sqrt{npq} = 2.233

P (x≤100) = P(z = P(z<0.34) = 0.63307.

6 0
3 years ago
PLEASE HELP ME THIS THING IS DUE TOMORROW. 14 feet ≈ ? meters
ddd [48]
14 feet=4.267214 meters
3 0
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