Answer:
I'm not an expert here, this is a best guess!
But I would say if there is no chance that of him incurring excess costs of less than $500, then he knows without insurance he'll end up paying at least $500, possibly more out of pocket, without the insurance.
so I would say He ends up spending the least amount out if pocket by going with option A. for $75. that's $75 out of pocket with no deductible and it covers his $500+ in excess costs....B and C would also cover the excess, but would each cost $140 or $275 out of pocket at the end of the day....
with that being said, I'd say it's worth it to buy the insurance....even if he doesn't have any excess costs, he's spent $75 dollars for the peace of mind to know he's covered either way, and if he does incur the excess costs he's spent $75 rather that $500+....Even if the excess charges are only $100, which it says there is no chance of happening, but still, then he's still saved $25 altogether. Unless I'm reading it wrong, Option A saves him the most money either way, and is worth it to buy the insurance!
Answer:
293.38 pounds
Step-by-step explanation:
We are given that
Distance between poles=35 feet
Weight of cable=10.4 per linear foot
We have to find the weight of the cable.
Differentiate w.r.t
Let 
![s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B2%7D%7B0.0225%7D%5Ctimes%5Cfrac%7B2%7D%7B3%7D%5Bt%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%5D%5E%7B17.5%7D_%7B0%7D)
![s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D2%5Ctimes%20%5Cfrac%7B2%7D%7B3%5Ctimes0.0225%7D%5B%281%2B0.0255x%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%5D%5E%7B17.5%7D_%7B0%7D)
s=28.21
Weight of cable=
pound
Answer:
75 of additional money
Step-by-step explanation:
5% of 1,500 is 75
and 1,500 plus 75 is 1575
